Question

我有一张excel表，里面有一堆关于停靠点的信息送货卡车全天制作。我可以成功提取 xlrd需要的信息。这是我正在使用的代码：

book = xlrd.open_workbook(r'c:\xytest.xls') 
sheet= book.sheet_by_index(0) 
odList = [] 
for i in range(1,6125): 
   cID = sheet.row(i)[0].value #Company ID 
   tID = sheet.row(i)[1].value #Truck ID 
   xyCoord = sheet.row_values(i,start_colx = 8,end_colx = 10 ) #long 
   and lat 
   xyCoord.reverse() #reversed, so that lat,long is in correct format 
   odList.append([cID,tID,xyCoord])

打印odList给我输出字段为：

[CompanyID,TruckID, Lat,Long] I get [[5000020.0, 1.0, [35.779999, 
-78.115784]], [5000020.0, 1.0, [36.075812, -78.256766]], [5000020.0, 
1.0, [35.779999, -78.115784]], [5000020.0, 2.0, [35.79528, 
-78.137549]], [5000020.0, 3.0, [35.79528, -78.137549]]

我使用列表索引来获取坐标并使用以下命令查询gmaps：

result = gmaps.directions(odList[0][2],odList[1][2]) 
time = result['Directions']['Duration']['seconds'] 
dist = result['Directions']['Distance']['meters']

不幸的是，gmaps不理解[35.779999，-78.115784]， [36.075812，-78.256766]，gmaps确实理解（35.779999，-78.115784），（36.075812，-78.256766）。关于如何获取查询send（）的任何想法代替 [] ？ `

Answer 1

尝试使用元组(var1, var2)或(var,)代替列表[var1, var2]，或在发送打印tuple([var])之前将列表转换为元组。

Answer 2

而不是：

xyCoord = sheet.row_values(i,start_colx = 8,end_colx = 10 ) #long and lat 
xyCoord.reverse() #reversed, so that lat,long is in correct format 
odList.append([cID,tID,xyCoord])

这样做：

lon, lat = sheet.row_values(i, start_colx=8, end_colx=10)
odList.append([cID, tID, (lat, lon))

谷歌地图API帮助或列表索引输出

2 个答案: