Question

我有一个包含以下结果的数组

red 
red
red
blue
blue
Green
White
Grey

我希望获得数组的每个值的重复计数，例如：

red    Count=3
blue   Count=2
Green  Count=1
White  Count=1
Grey   Count=1

Answer 1

LINQ让这一切变得简单：

Dictionary<string, int> counts = array.GroupBy(x => x)
                                      .ToDictionary(g => g.Key,
                                                    g => g.Count());

Answer 2

将它们添加到词典中：

Dictionary<string, int> counts = new Dictionary<string, int>();
foreach(string s in list) 
{
   int prevCount;
   if (!counts.TryGet(s, out prevCount))
   {
      prevCount.Add(s, 1);
   }
   else
   {   
       counts[s] = prevCount++;
   }
}

然后count包含字符串作为键，以及它们作为值出现。

Answer 3

嗯这是一项非常艰巨的任务，但Captain Algorithm会帮助你！他告诉我们，有很多方法可以做到这一点。其中一个他给我，我把它给你：

Dictionary <object, int> tmp = new Dictionary <object, int> ();

foreach (Object obj in YourArray)
  if (!tmp.ContainsKey(obj))
    tmp.Add (obj, 1);
 else tmp[obj] ++;

tmp.Values;//Contains counts of elements

Answer 4

上面有点错误，正确的代码是：

string[] arr = { "red", "red", "blue", "green", "Black", "blue", "red" };

var results = from str in arr
              let c = arr.Count( m => str.Contains(m.Trim()))
              select str + " count=" + c;

foreach(string str in results.Distinct())
    Console.WriteLine(str);

Answer 5

制作另一个计数数组....并在原始数组上循环，条件是如果它发现红色递增计数数组的第一个单元格......如果它发现蓝色递增计数数组中的第二个单元格。 ...等等。祝你好运。

Answer 6

Hashtable ht = new Hashtable();
foreach (string s in inputStringArray)
{
    if (!ht.Contains(s))
    {
        ht.Add(s, 1);
    }
    else
    {
        ht[s] = (int)ht[s] + 1;
    }
}

Answer 7

我认为这应该可以解决问题

    string[] arr = { "red", "red", "blue", "green", "Black", "blue", "red" };

    var results = from str in arr
                  let c = arr.Count( m => str.Contains(m.Trim()))
                  select str + " count=" + str;

    foreach(string str in results.Distinct())
        Console.WriteLine(str);

输出：

red count=3
blue count=2
green count=1
Black count=1

列表数组重复计数

7 个答案: