由于某些原因,此代码仍返回2而不是1?
$allowedCount = 1; ( This figure is set inside the database )
$sql_count = mysql_query("SELECT usrid FROM mytable WHERE usrid=".$uid) or die(mysql_error());
$currentCount = mysql_num_rows( $sql_count );
$currentCount = 1; ( In this example current count returns a 1 )
if ( $currentCount <= $allowedCount ) {
// do this OK
} else {
// do this Not OK
}
我想要做的是检查用户是否已达到其限制,如果是,则禁止他们进一步INSERT查询等....
这是一种简单的方法吗?
答案 0 :(得分:0)