我尝试完成的是使用GDataXML
获取RSS2 Feed项的src属性。 Feed的项目xml是这样的:
<item>
<title>BlackBerry EMEA servers crash</title>
<link>http://www.mysite.com/?p=672</link>
<comments>http://www.mysite.com/?p=672#comments</comments>
<pubDate>Mon, 10 Oct 2011 21:11:24 +0000</pubDate>
<dc:creator>acreator</dc:creator>
<category><![CDATA[Latest News]]></category>
<description><![CDATA[<span class="image-rss"><a href="http://www.mysite.com/?p=672"><img title="BlackBerry EMEA servers crash" src="http://www.mysite.com/wp-content/uploads/2011/10/blackberry-thumb-medium-300x187.jpg" alt="BlackBerry EMEA servers crash" width="200" height="124" /></a></span><br/>yada yada yada]]></description>
</item>
我目前使用的代码,解析得非常好<description>
,<title>
,<link>
;和<pubdate>
;但<img>
;失败了。这是代码:
NSArray *channels = [rootElement elementsForName:@"channel"];
for (GDataXMLElement *channel in channels) {
NSArray *items = [channel elementsForName:@"item"];
for (GDataXMLElement *item in items) {
GDataXMLElement *articleDesc = [item elementForChild:@"description"];
NSArray *imgs = [articleDesc nodesForXPath:@"//img[@src]" error:nil];
NSString *articleTitle = [item valueForChild:@"title"];
NSString *url = [item valueForChild:@"link"];
NSString *articleDateString = [item valueForChild:@"pubDate"];
Article *entry = [[[Article alloc] initWithTitle:articleTitle
url:url
date:articleDate] autorelease];
[entries addObject:entry];
}
}
当我打印到控制台 articleDesc
的说明时,我会收到以下信息:
GDataXMLElement 0x70503b0: {type:1 name:description xml:"<description><span class="image-rss"><a href="http://www.mysite.com/?p=672"><img title="BlackBerry EMEA servers crash" src="http://www.mysite.com/wp-content/uploads/2011/10/blackberry-thumb-medium-300x187.jpg" alt="BlackBerry EMEA servers crash" width="200" height="124" /></a></span><br/>RIM has confirmed that…</description>"}
是否可以使用“快速”src
解析 GDataXML
属性,或者我必须使用正则表达式进行解析?
非常欢迎所有建议。
答案 0 :(得分:2)
我遇到了同样的问题并找到了解决方案。它应该是这样的:
NSArray *imgs = [articleDesc nodesForXPath:@"//img/@src" error:nil];