有没有办法将System.IO.Stream转换为Windows.Storage.Streams.IRandomAccessStream?

时间:2011-10-06 00:46:54

标签: c# .net windows windows-8

在Windows 8中;我想将MemoryStream的内容传递给一个接受类型为Windows.Storage.Streams.IRandomAccessStream的参数的类。有没有办法将这个MemoryStream转换为IRandomAccessStream?

7 个答案:

答案 0 :(得分:93)

要使用扩展程序:您必须添加“using System.IO”

在Windows8中,.NET和WinRT类型通常会转换为兼容类型,因此您无需关心它。

但是,对于流,有一些帮助方法可以在WinRT和.NET流之间进行转换: 对于从WinRT流转换 - > .NET流:

InMemoryRandomAccessStream win8Stream = GetData(); // Get a data stream from somewhere.
System.IO.Stream inputStream = win8Stream.AsStream()

从.NET流转换 - > WinRT流:

Windows.Storage.Streams.IInputStream inStream = stream.AsInputStream();
Windows.Storage.Streams.IOutputStream outStream = stream.AsOutputStream();

更新时间:2013-09-01

不要说微软不听它的开发者社区;)

announcement for .NET FX 4.5.1中,Microsoft声明:

  

许多人一直想要一种将.NET Stream转换为Windows运行时IRandomAccessStream的方法。我们只需将其称为AsRandomAccessStream扩展方法。我们无法将此功能引入Windows 8,但它是我们首次添加Windows 8.1预览版。

     

您现在可以编写以下代码,使用HttpClient下载图像,将其加载到BitmapImage中,然后设置为Xaml Image控件的源。

    //access image via networking i/o
    var imageUrl = "http://www.microsoft.com/global/en-us/news/publishingimages/logos/MSFT_logo_Web.jpg";
    var client = new HttpClient();
    Stream stream = await client.GetStreamAsync(imageUrl);
    var memStream = new MemoryStream();
    await stream.CopyToAsync(memStream);
    memStream.Position = 0;
    var bitmap = new BitmapImage();
    bitmap.SetSource(memStream.AsRandomAccessStream());
    image.Source = bitmap;

HTH。

答案 1 :(得分:7)

找到更优雅的解决方案:

public static class MicrosoftStreamExtensions
{
    public static IRandomAccessStream AsRandomAccessStream(this Stream stream)
    {
        return new RandomStream(stream);
    }

}

class RandomStream : IRandomAccessStream
{
    Stream internstream;

    public RandomStream(Stream underlyingstream)
    {
        internstream = underlyingstream;
    }

    public IInputStream GetInputStreamAt(ulong position)
    {
        //THANKS Microsoft! This is GREATLY appreciated!
        internstream.Position = (long)position;
        return internstream.AsInputStream();
    }

    public IOutputStream GetOutputStreamAt(ulong position)
    {
        internstream.Position = (long)position;
        return internstream.AsOutputStream();
    }

    public ulong Size
    {
        get
        {
            return (ulong)internstream.Length;
        }
        set
        {
            internstream.SetLength((long)value);
        }
    }

    public bool CanRead
    {
        get { return this.internstream.CanRead; }
    }

    public bool CanWrite
    {
        get { return this.internstream.CanWrite; }
    }

    public IRandomAccessStream CloneStream()
    {
        throw new NotSupportedException();
    }

    public ulong Position
    {
        get { return (ulong)this.internstream.Position; }
    }

    public void Seek(ulong position)
    {
        this.internstream.Seek((long)position, SeekOrigin.Begin);
    }

    public void Dispose()
    {
        this.internstream.Dispose();
    }

    public Windows.Foundation.IAsyncOperationWithProgress ReadAsync(IBuffer buffer, uint count, InputStreamOptions options)
    {
        return this.GetInputStreamAt(this.Position).ReadAsync(buffer, count, options);
    }

    public Windows.Foundation.IAsyncOperation FlushAsync()
    {
        return this.GetOutputStreamAt(this.Position).FlushAsync();
    }

    public Windows.Foundation.IAsyncOperationWithProgress WriteAsync(IBuffer buffer)
    {
        return this.GetOutputStreamAt(this.Position).WriteAsync(buffer);
    }
}

答案 2 :(得分:5)

经过一些实验后,我发现以下代码正在运行。

using System;
using System.IO;
using System.Threading.Tasks;
using Windows.Storage.Streams;

partial class MainPage
{
    public MainPage()
    {
        var memoryStream = new MemoryStream(new byte[] { 65, 66, 67 });
        ConvertToRandomAccessStream(memoryStream, UseRandomAccessStream);
        InitializeComponent();
    }

    void UseRandomAccessStream(IRandomAccessStream stream)
    {
        var size = stream.Size;
    } // put breakpoint here to check size

    private static async void ConvertToRandomAccessStream(MemoryStream memoryStream,
         Action<IRandomAccessStream> callback)
    {
        var randomAccessStream = new InMemoryRandomAccessStream();
        var outputStream = randomAccessStream.GetOutputStreamAt(0);
        var dw = new DataWriter(outputStream);
        var task = new Task(() => dw.WriteBytes(memoryStream.ToArray()));
        task.Start();
        await task;
        await dw.StoreAsync();
        var success = await outputStream.FlushAsync();
        callback(randomAccessStream);
    }
}

更新:我还尝试了更优雅的方法实现:

    private static void ConvertToRandomAccessStream(MemoryStream memoryStream,
        Action<IRandomAccessStream> callback)
    {
        var randomAccessStream = new InMemoryRandomAccessStream();
        var outputStream = randomAccessStream.GetOutputStreamAt(0);
        RandomAccessStream.Copy(memoryStream.AsInputStream(), outputStream);
        callback(randomAccessStream);
    }

奇怪的是,它不起作用。当我稍后致电stream.Size时,我得到零。

UPDATE我更改了函数以返回IRandomAccessStream而不是使用回调函数

public static async Task<IRandomAccessStream> ConvertToRandomAccessStream(MemoryStream memoryStream)
{
    var randomAccessStream = new InMemoryRandomAccessStream();

    var outputStream = randomAccessStream.GetOutputStreamAt(0);
    var dw = new DataWriter(outputStream);
    var task = new Task(() => dw.WriteBytes(memoryStream.ToArray()));
    task.Start();

    await task;
    await dw.StoreAsync();

    await outputStream.FlushAsync();

    return randomAccessStream;
}

答案 3 :(得分:4)

Windows 8上没有内置方法。对于Windows 8.1,我们添加了一个Stream.AsRandomAccessStream()扩展方法:

internal static IRandomAccessStream ToRandomAccessStream(byte[] array)
{
    MemoryStream stream = new MemoryStream(array);
    return stream.AsRandomAccessStream();
}

答案 4 :(得分:3)

以上都不适用于我(可能是自答案发布以来的一些API更改)。唯一有效的方法是

IRandomAccessStream inMemoryStream = new InMemoryRandomAccessStream();
using (var inputStream = stream.AsInputStream())
{
    await RandomAccessStream.CopyAsync(inputStream, inMemoryStream);
}
inMemoryStream.Seek(0);

答案 5 :(得分:0)

此代码段将流(stream)转换为实现ims的InMemoryRandomAccessStream(IRandomAccessStream)。诀窍是必须在后台线程上调用CopyTo。

        InMemoryRandomAccessStream ims = new InMemoryRandomAccessStream();
        var imsWriter = ims.OpenWrite();
        await Task.Factory.StartNew(() => stream.CopyTo(imsWriter));

答案 6 :(得分:0)

看一下这个链接:

How To Convert Byte Array To IRandomAccessStream

它还提供了一个字节数组构造函数的示例和实现(以及一个用于.NET流的构造函数),如果您想使用SetSource类的SetSourceAsyncBitmapImage方法,则非常有用(如我的情况)。

希望这有助于某人...