Question

我有两个文本文件，master.txt和926.txt。如果926.txt中有一行不在master.txt中，我想写一个新文件notinbook.txt。

我写了我能想到的最好的东西，但鉴于我是一个可怕的/新手程序员，它失败了。这就是我所拥有的

g = File.new("notinbook.txt", "w")
File.open("926.txt", "r") do |f|
  while (line = f.gets)
    x = line.chomp
    if
      File.open("master.txt","w") do |h|
      end
      while (line = h.gets)
        if line.chomp != x
          puts line
        end
      end
    end
  end
end
g.close

当然，它失败了。谢谢！

Answer 1

这应该有效：

f1 = IO.readlines("926.txt").map(&:chomp)
f2 = IO.readlines("master.txt").map(&:chomp)

File.open("notinbook.txt","w"){ |f| f.write((f1-f2).join("\n")) }

这是我的测试：

<强> 926.txt

line1
line2
line3
line4
line5

<强> master.txt

line1
line2
line4

<强> notinbook.txt

line3
line5

Answer 2

您可以这样做：

master_lines = []
File.open("notinbook.txt","w") do |result|
  File.open("master.txt","r") do |master|
    master.each_line do |line|
      master_lines << line.chomp
    end
  end

  File.open("926.txt","r") do |query|
    query.each_line do |line|
      if !master_lines.include? line.chomp
        result.puts line.chomp
      end
    end
  end
end

Answer 3

使用：http://raa.ruby-lang.org/project/compare/

OR

％x（diff file1 file2）

OR

http://github.com/myobie/htmldiff/

Answer 4

希望这有帮助

dir = File.dirname(__FILE__)
notinbook = "#{dir}/notinbook.txt"
master    = "#{dir}/master.txt"
f926      = "#{dir}/926.txt"

def file_into_ary(file)
  ary = []
  File.open(file).each{ |line| ary << line }
  return ary
end

def write_difference(file, diff)
  File.open(file, 'w') do |file|  
    diff.each do |line|
      file.write(line)
    end
  end 
end

diff = file_into_ary(f926) - file_into_ary(master)
write_difference(notinbook, diff) unless diff.empty?

尝试比较两个文本文件，并根据信息创建第三个文本文件

4 个答案: