我正在处理包含一些程序的包,我遇到了一些麻烦。当我尝试测试将加仑转换为升或其他过程的过程时,它只打印出未命名块中声明的内容而不是转换数字。有什么想法吗?
CREATE OR REPLACE PACKAGE eng_metric
IS
PROCEDURE convert(degree_fahrenheit IN OUT NUMBER,degree_celsius IN OUT NUMBER,measure IN VARCHAR2);
PROCEDURE convert(liters IN OUT NUMBER,gallons IN OUT NUMBER);
END eng_metric;
/
CREATE OR REPLACE PACKAGE BODY eng_metric
AS
PROCEDURE Convert
(degree_fahrenheit IN OUT NUMBER,
degree_celsius IN OUT NUMBER,
measure IN VARCHAR2)
IS
df NUMBER;
dc NUMBER;
convertf NUMBER;
measurecf VARCHAR2(4);
BEGIN
measurecf := measure;
df := degree_fahrenheit;
dc := degree_celsius;
IF measure = 'TEMP' THEN
IF dc = NULL THEN
convertf := ((df - 32) * .56);
degree_fahrenheit := convertf;
dbms_output.Put_line('The temperature in fahrenheit is '
||To_char(degree_fahrenheit));
ELSIF df = NULL THEN
convertf := (dc + 17.98) * 1.8;
degree_celsius := convertf;
END IF;
ELSE
dbms_output.Put_line('Invalid measure');
END IF;
END convert;
PROCEDURE Convert
(liters IN OUT NUMBER,
gallons IN OUT NUMBER)
IS
lit NUMBER;
gal NUMBER;
convertlg NUMBER;
BEGIN
lit := liters;
gal := gallons;
IF gal = NULL THEN
convertlg := (lit / 3.785);
liters := convertlg;
ELSIF lit = NULL THEN
convertlg := (gal * 3.785);
gallons := convertlg;
END IF;
END convert;
END eng_metric;
/
DECLARE
liters NUMBER := 25;
gallons NUMBER := 41;
nully NUMBER := NULL;
BEGIN
eng_metric.Convert(nully,gallons);
dbms_output.Put_line(To_char(gallons));
END;
/
答案 0 :(得分:4)
而不是
IF gal = NULL THEN
你需要
IF gal IS NULL
答案 1 :(得分:0)
你必须记住的是,NULL意味着“没有价值”。它永远不等于或不能等于任何东西,包括NULL。因此,您需要使用IS NULL或IS NOT NULL,或使用NVL函数将null更改为具有值的值。