Question

我正在尝试运行一个简单的C ++程序（因为我刚开始学习C ++）并尝试将这个示例代码作为一个程序添加两个数字。当我执行程序时，我从来没有得到错误，但c总是返回0.帮助??

#include <iostream.h>

int Add (int x, int y)
{

    std::cout << "In Add(), received " << x << " and " << y << "\n";
    return 0;
}

int main()
{
    std::cout << "I'm in main()!\n";
    int a, b, c;
    std::cout << "Enter two numbers here: ";
    cin >> a;
    cin >> b;
    std::cout << "\nCalling Add()\n";
    c=Add(a,b);
    std::cout << "\nBack in main().\n";
    std::cout << "c was set to " << c;
    std::cout << "\nExiting...\n\n";
    return 0;
}

提前致谢。

Answer 1

由于Add返回0，c 总是为0.您需要，实际上，将您传递的数字添加到Add并返回来自该函数。

Answer 2

给它一个旋转。注意：添加返回（x + y）

    #include <iostream>

    using namespace std;

    int Add(int x, int y)
    {
         std::cout << "In Add(), received " << x << " and " << y << std::endl;
         return (x+y);
    }

    int main()
    {
         std::cout << "I'm in main()!\n";
         int a, b, c;
         std::cout << "Enter two numbers: ";
         std::cin >> a;
         std::cin >> b;
         std::cout << "\nCalling Add()\n";
         c=Add(a,b);
         std::cout << "\nBack in main().\n";
         std::cout << "c was set to " << c;
         std::cout << "\nExiting...\n\n";
         return 0;
    }

Answer 3

你的Add函数总是返回0，所以c始终为0是个谜？ :)它应该是return x + y。

执行功能时出现问题

3 个答案: