Question

好的..所以基本上，我们有一个链接：

$url = "http://www.site.com/index.php?sub=Mawson&state=QLD&cat=4&page=2&sort=z";

基本上，我需要创建一个替换URL中每个内容的函数，例如：

<a href="<?=$url;?>?sort=a">Sort by A-Z</a>
<a href="<?=$url;?>?sort=z">Sort by Z-A</a>

或者，另一个例子：

<a href="<?=$url;?>?cat=1">Category 1</a>
<a href="<?=$url;?>?cat=2">Category 2</a>

或者，另一个例子：

<a href="<?=$url;?>?page=1">1</a>
<a href="<?=$url;?>?page=2">2</a>
<a href="<?=$url;?>?page=3">3</a>
<a href="<?=$url;?>?page=4">4</a>

基本上，我们需要一个函数来替换URL中的特定$_GET，这样我们就不会得到重复内容，例如：?page=2&page=3

话虽如此，它需要很聪明，因此它知道参数的开头是?还是&

我们还需要它是聪明的，以便我们可以像这样使用URL：

<a href="<?=$url;?>page=3">3</a> (without the ? - so it will detect automatically wether to use an `&` or a `?`

我不介意为某些$ _GET参数为每个preg_replace创建不同的变量，但我正在寻找最佳方法。

谢谢。

Answer 1

这样的事情怎么样？

function merge_querystring($url = null,$query = null,$recursive = false)
{
  // $url = 'http://www.google.com.au?q=apple&type=keyword';
  // $query = '?q=banana';
  // if there's a URL missing or no query string, return
  if($url == null)
    return false;
  if($query == null)
    return $url;
  // split the url into it's components
  $url_components = parse_url($url);
  // if we have the query string but no query on the original url
  // just return the URL + query string
  if(empty($url_components['query']))
    return $url.'?'.ltrim($query,'?');
  // turn the url's query string into an array
  parse_str($url_components['query'],$original_query_string);
  // turn the query string into an array
  parse_str(parse_url($query,PHP_URL_QUERY),$merged_query_string);
  // merge the query string
  if($recursive == true)
    $merged_result = array_merge_recursive($original_query_string,$merged_query_string);
  else
    $merged_result = array_merge($original_query_string,$merged_query_string);
  // Find the original query string in the URL and replace it with the new one
  return str_replace($url_components['query'],http_build_query($merged_result),$url);
}

...使用

<a href="<?=merge_querystring($url,'?page=1');?>">Page 1</a>
<a href="<?=merge_querystring($url,'?page=2');?>">Page 2</a>

Answer 2

嗯，我有同样的问题，发现了这个问题，最后，我更喜欢自己的方法。也许它有缺陷，那么请告诉我它们是什么。我的解决方案是：

$query=$_GET;
$query['YOUR_NAME']=$YOUR_VAL;
$url=$_SERVER['PHP_SELF']. '?' .  http_build_query($query);

希望它有所帮助。

Answer 3

<?php
function change_query ( $url , $array ) {
    $url_decomposition = parse_url ($url);
    $cut_url = explode('?', $url);
    $queries = array_key_exists('query',$url_decomposition)?$url_decomposition['query']:false;
    $queries_array = array ();
    if ($queries) {
        $cut_queries   = explode('&', $queries);
        foreach ($cut_queries as $k => $v) {
            if ($v)
            {
                $tmp = explode('=', $v);
                if (sizeof($tmp ) < 2) $tmp[1] = true;
                $queries_array[$tmp[0]] = urldecode($tmp[1]);
            }
        }
    }
    $newQueries = array_merge($queries_array,$array);
    return $cut_url[0].'?'.http_build_query($newQueries);
}
?>

像这样使用：

<?php
    echo change_query($myUrl, array('queryKey'=>'queryValue'));
?>

我今天早上这样做，似乎在所有情况下都有效。您可以使用数组更改/添加多个查询;）

Answer 4

function replaceQueryParams($url, $params)
{
    $query = parse_url($url, PHP_URL_QUERY);
    parse_str($query, $oldParams);

    if (empty($oldParams)) {
        return rtrim($url, '?') . '?' . http_build_query($params);
    }

    $params = array_merge($oldParams, $params);

    return preg_replace('#\?.*#', '?' . http_build_query($params), $url);
}

$url示例：

$params示例：

[
   'foo' => 'not-bar',
]

注意：它无法理解包含锚点（哈希）的网址，例如http://example.com/page?foo=bar#section1

Answer 5

如果我正确读到这个，我可能不会。你知道你要在url字符串中替换哪个GET吗？这可能很草率但是......

$url_pieces = explode( '?', $url );
$var_string = $url_pieces[1].'&';
$new_url = $url_pieces[0].preg_replace( '/varName\=value/', 'newVarName=newValue', $var_string );

这是我的看法，祝你好运。

Answer 6

我不知道这是否是你想要完成的事情，但无论如何它仍然存在：

<?php
    function mergeMe($url, $assign) {
        list($var,$val) = explode("=",$assign);
        //there's no var defined
        if(!strpos($url,"?")) {
            $res = "$url?$assign";
        } else {
            list($base,$vars) = explode("?",$url);
            //if the vars dont include the one given
            if(!strpos($vars,$var)) {
                $res = "$url&$assign";
            } else {
                $res = preg_replace("/$var=[a-zA-Z0-9_]*(&|$)/",$assign."&",$url);
                $res = preg_replace("/&$/","",$res); //remove possible & at the end
            }
        }
        //just to show the difference, should be "return $res;" instead
        return "$url <strong>($assign)</strong><br>$res<hr>";
    }

    //example
    $url1 = "http://example.com";
    $url2 = "http://example.com?sort=a";
    $url3 = "http://example.com?sort=a&page=0";
    $url4 = "http://example.com?sort=a&page=0&more=no";

    echo mergeMe($url1,"page=4");
    echo mergeMe($url2,"page=4");
    echo mergeMe($url3,"page=4");
    echo mergeMe($url4,"page=4");
?>

Answer 7

改善Scuzzy 2013功能最后一块用于清理url查询字符串。

// merge the query string
// array_filter removes empty query array
    if ($recursive == true) {
        $merged_result = array_filter(array_merge_recursive($original_query_string, $merged_query_string));
    } else {
        $merged_result = array_filter(array_merge($original_query_string, $merged_query_string));
    }

    // Find the original query string in the URL and replace it with the new one
    $new_url = str_replace($url_components['query'], http_build_query($merged_result), $url);

    // If the last query string removed then remove ? from url 
    if(substr($new_url, -1) == '?') {
       return rtrim($new_url,'?');
    }
    return $new_url;

Answer 8

<?php
//current url: http://localhost/arters?sub=Mawson&state=QLD&cat=4&page=2&sort=a

function change_query($queryKey, $queryValue){
    $queryStr = $_SERVER['QUERY_STRING'];
    parse_str($queryStr, $output);
    $output[$queryKey] = $queryValue;
    return http_build_query($output);
}

用法：

<a href="?<?=change_query("sort",'z');?>">sort by z</a>

// http://localhost/arters?sub=Mawson&state=QLD&cat=4&page=2&sort=z

<a href="?<?=change_query("page",'5');?>">Page 5</a>

// http://localhost/arters?sub=Mawson&state=QLD&cat=4&page=5&sort=a

更好地替换给定URL中的查询字符串值的方法

8 个答案: