我正在寻找XSLT的一些帮助,将一个xml文件转换为另一种格式。
输入xml文件如下:
<PATIENTLIST ELAPSEDMS="234" >
<PATIENT ID="MGH000007">
<ADDRESS1>550 BREZHNEV ST</ADDRESS1>
<ADDRESS2></ADDRESS2>
<CITY>MOSCOW</CITY>
<STATE>MA</STATE>
<ZIP>02139</ZIP>
<COUNTRY ISO3166-1="USSR"></COUNTRY>
<DATEOFBIRTH>1934/04/10</DATEOFBIRTH>
<DAYPHONE>(617) 111-1111 </DAYPHONE>
<FIRSTNAME>TEST</FIRSTNAME>
<HOMEPHONE>(617) 111-1111</HOMEPHONE>
<LASTNAME>TEST MGH</LASTNAME>
<LIMITEDACCESS>False</LIMITEDACCESS>
<MARITALSTATUS>SINGLE</MARITALSTATUS>
<MEDICALRECORDNUMBERS>
<MEDICALRECORDNUMBER>
<SITE>BWH</SITE>
<STATUS>A</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
<MEDICALRECORDNUMBER>
<SITE>BWI</SITE>
<STATUS>A</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
<MEDICALRECORDNUMBER>
<SITE>MEEI</SITE>
<STATUS>A</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
<MEDICALRECORDNUMBER>
<SITE>MGH</SITE>
<STATUS>A</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
<MEDICALRECORDNUMBER>
<SITE>SHC</SITE>
<STATUS>A</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
<MEDICALRECORDNUMBER>
<SITE>OLD #</SITE>
<STATUS>M</STATUS>
<VALUE>0000007</VALUE>
</MEDICALRECORDNUMBER>
</MEDICALRECORDNUMBERS>
<MIDDLEINITIAL>R</MIDDLEINITIAL>
<MOTHERSMAIDENNAME></MOTHERSMAIDENNAME>
<MRNR>0000007</MRNR>
<NAME>TEST MGH, TEST R</NAME>
<NAMESUFFIX></NAMESUFFIX>
<NAMEPREFIX></NAMEPREFIX>
<PRIMARYCAREPROVIDERID>512513</PRIMARYCAREPROVIDERID>
<PRIMARYLANGUAGE>ENGLISH</PRIMARYLANGUAGE>
<RACE CODE1="BLACK" CODE2="" FREETEXT="">BLACK</RACE>
<ETHNICITY CODE1="AFRICAN AMERICAN" CODE2="" FREETEXT="">AFRICAN AMERICAN</ETHNICITY>
<RELIGION>NO PREFERENCE</RELIGION>
<SEX>M</SEX>
<SSN></SSN>
<UID>101662537</UID>
<VETERAN>NO</VETERAN>
</PATIENT>
</PATIENTLIST>
输出文件需要如下所示:
<?xml version="1.0" encoding="utf-8" ?>
<eCliPSEDataIntegrationServiceRequest xmlns="http://iocent.com/eCliPSEDataIntegrationServiceRequest.xsd">
<PatientIdentifierRecord MedicalRecordNumber="MGH000007" LastName="Person" FirstName="Test" MiddleInitial="A" DateOfBirth="04/10/1934" Operation="Add" OverwriteExistingData="true" />
<PatientDataRecord MedicalRecordNumber="MGH000007" ParameterName="Gender" ParameterValue="2" TimeStamp="8/30/2011" Operation="Add" OverwriteExistingData="true" />
<PatientDataRecord MedicalRecordNumber="MGH000007" ParameterName="Race" ParameterValue="1" TimeStamp="8/30/2011" Operation="Add" OverwriteExistingData="true" />
</eCliPSEDataIntegrationServiceRequest>
所以我想拔出
患者ID并将其用作MedicalRecordNumber = value
DATEOFBIRTH节点作为DateOfBirth值 - 格式从YYYY / MM / DD更改为MM / DD / YYYY
FIRSTNAME节点成为FirstName的值
LASTNAME节点成为LastName的值
MIDDLEINITIAL节点成为MiddleInitial的值
SEX节点成为Gender Male = 1,Female = 2
的值RACE节点成为竞赛价值 - 基于查询表(高加索人= 1,非裔美国人= 2等) -
因此,我需要提取这些值,更改格式,在某些情况下执行类似表格的翻译(针对性别和种族),并以新格式写出文件。
我仅限于XSLT 1.0
我是XSLT的新手,因此非常感谢任何帮助!!!
谢谢!
答案 0 :(得分:1)
我很欣赏上面收到的开头。我发布了我想出的xslt来解决我的问题:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:variable name='newline'><xsl:text>
</xsl:text>
</xsl:variable>
<xsl:variable name='MRN'>
<xsl:value-of select="PATIENTLIST/PATIENT/@ID"/>
</xsl:variable>
<xsl:variable name='Gender'>
<xsl:if test="PATIENTLIST/PATIENT/SEX='M'">1</xsl:if>
<xsl:if test="PATIENTLIST/PATIENT/SEX='F'">2</xsl:if>
</xsl:variable>
<xsl:variable name='RaceIn'>
<xsl:value-of select="PATIENTLIST/PATIENT/RACE"/>
</xsl:variable>
<xsl:variable name='Race'>
<xsl:choose>
<xsl:when test="$RaceIn='WHITE'">1</xsl:when>
<xsl:when test="$RaceIn='BLACK'">2</xsl:when>
<xsl:when test="$RaceIn='HISPANIC'">3</xsl:when>
<xsl:when test="$RaceIn='ASIAN'">4</xsl:when>
<xsl:when test="$RaceIn='NATIVE AMERICAN'">5</xsl:when>
<xsl:when test="$RaceIn='INDIAN'">5</xsl:when>
<xsl:otherwise>7</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:variable name='CurrDate'>
<xsl:value-of select="'MM/DD/YYY'"/>
</xsl:variable>
<xsl:variable name='Operation'>
<xsl:value-of select="'Add'"/>
</xsl:variable>
<xsl:variable name='Overwrite'>
<xsl:value-of select="'true'"/>
</xsl:variable>
<xsl:template match="/">
<xsl:text>
</xsl:text>
<eCliPSEDataIntegrationServiceRequest >
<xsl:text>
</xsl:text>
<PatientIdentifierRecord>
<xsl:attribute name="MedicalRecordNumber">
<xsl:value-of select="$MRN"/>
</xsl:attribute>
<xsl:attribute name="LastName">
<xsl:value-of select="PATIENTLIST/PATIENT/LASTNAME"/>
</xsl:attribute>
<xsl:attribute name="FirstName">
<xsl:value-of select="PATIENTLIST/PATIENT/FIRSTNAME"/>
</xsl:attribute>
<xsl:attribute name="MiddleInitial">
<xsl:value-of select="PATIENTLIST/PATIENT/MIDDLEINITIAL"/>
</xsl:attribute>
<xsl:attribute name="DateOfBirth">
<xsl:value-of select="PATIENTLIST/PATIENT/DATEOFBIRTH"/> <!-- do we need to change the date format?-->
</xsl:attribute>
<xsl:attribute name="Operation">
<xsl:value-of select="$Operation"/>
</xsl:attribute>
<xsl:attribute name="OverwriteExistingData">
<xsl:value-of select="$Overwrite"/>
</xsl:attribute>
</PatientIdentifierRecord>
<xsl:text>
</xsl:text>
<PatientDataRecord>
<xsl:attribute name="MedicalRecordNumber">
<xsl:value-of select="$MRN"/>
</xsl:attribute>
<xsl:attribute name="ParameterName">
<xsl:value-of select="'Gender'"/>
</xsl:attribute>
<xsl:attribute name="ParameterValue">
<xsl:value-of select="$Gender"/>
</xsl:attribute>
<xsl:attribute name="Timestamp">
<xsl:value-of select="$CurrDate"/>
</xsl:attribute>
<xsl:attribute name="Operation">
<xsl:value-of select="$Operation"/>
</xsl:attribute>
<xsl:attribute name="OverwriteExistingData">
<xsl:value-of select="$Overwrite"/>
</xsl:attribute>
</PatientDataRecord>
<xsl:text>
</xsl:text>
<PatientDataRecord>
<xsl:attribute name="MedicalRecordNumber">
<xsl:value-of select="$MRN"/>
</xsl:attribute>
<xsl:attribute name="ParameterName">
<xsl:value-of select="'Race'"/>
</xsl:attribute>
<xsl:attribute name="ParameterValue">
<xsl:value-of select="$Race"/> <!-- this needs to be transformed based on race table and race_7_groups parameter -->
</xsl:attribute>
<xsl:attribute name="Timestamp">
<xsl:value-of select="$CurrDate"/> <!-- how do i get the current date?-->
</xsl:attribute>
<xsl:attribute name="Operation">
<xsl:value-of select="$Operation"/>
</xsl:attribute>
<xsl:attribute name="OverwriteExistingData">
<xsl:value-of select="$Overwrite"/>
</xsl:attribute>
</PatientDataRecord>
<xsl:text>
</xsl:text>
</eCliPSEDataIntegrationServiceRequest>
</xsl:template>
</xsl:stylesheet>
我仍然致力于获得当前日期的解决方案。我看过的选项 - 作为参数传入 - 编写脚本函数以获取当前日期
此外,我不确定是否需要将日期格式从YYYY / MM / DD更改为MM / DD / YYYY。
如果有人对上述两个主题有一些建议,他们会受到欢迎。
感谢
答案 1 :(得分:1)
根据反馈 - 我正在更新我的解决方案并在此处发布
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:variable name="smallcase" select="'abcdefghijklmnopqrstuvwxyz'" />
<xsl:variable name="uppercase" select="'ABCDEFGHIJKLMNOPQRSTUVWXYZ'" />
<xsl:variable name='MRN'>
<xsl:value-of select="PATIENTLIST/PATIENT/MRNR"/>
</xsl:variable>
<xsl:variable name='BirthDate'>
<xsl:value-of select="PATIENTLIST/PATIENT/DATEOFBIRTH"/>
</xsl:variable>
<xsl:variable name="BDayYear" select="substring($BirthDate,1,4)" />
<xsl:variable name="BDayMonth" select="substring($BirthDate,6,2)" />
<xsl:variable name="BDayDay" select="substring($BirthDate,9,2)" />
<xsl:variable name='BirthDateUse'>
<xsl:value-of select="concat($BDayMonth, '/', $BDayDay, '/', $BDayYear)"/>
</xsl:variable>
<xsl:variable name='Gender'>
<xsl:if test="translate(PATIENTLIST/PATIENT/SEX, $smallcase, $uppercase)='M'">1</xsl:if>
<xsl:if test="translate(PATIENTLIST/PATIENT/SEX, $smallcase, $uppercase)='F'">2</xsl:if>
</xsl:variable>
<xsl:variable name='RaceUC'>
<xsl:value-of select="translate(PATIENTLIST/PATIENT/RACE, $smallcase, $uppercase)"/>
</xsl:variable>
<xsl:variable name='Race'>
<xsl:choose>
<xsl:when test="$RaceUC='WHITE'">1</xsl:when>
<xsl:when test="$RaceUC='BLACK'">2</xsl:when>
<xsl:when test="$RaceUC='AFRICAN AMERICAN'">2</xsl:when>
<xsl:when test="$RaceUC='HISPANIC'">3</xsl:when>
<xsl:when test="$RaceUC='ASIAN'">4</xsl:when>
<xsl:when test="$RaceUC='NATIVE AMERICAN'">5</xsl:when>
<xsl:when test="$RaceUC='INDIAN'">6</xsl:when>
<xsl:otherwise>7</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:variable name='Operation'>
<xsl:value-of select="'Add'"/>
</xsl:variable>
<xsl:variable name='Overwrite'>
<xsl:value-of select="'true'"/>
</xsl:variable>
<xsl:template match="/">
<eCliPSEDataIntegrationServiceRequest xmlns="http://iocent.com/eCliPSEDataIntegrationServiceRequest.xsd">
<PatientIdentifierRecord
MedicalRecordNumber="{$MRN}"
LastName="{PATIENTLIST/PATIENT/LASTNAME}"
FirstName="{PATIENTLIST/PATIENT/FIRSTNAME}"
MiddleInitial="{PATIENTLIST/PATIENT/MIDDLEINITIAL}"
DateOfBirth ="{$BirthDate}"
Operation="{$Operation}"
OverwriteExistingData="{$Overwrite}"
/>
<PatientDataRecord
MedicalRecordNumber="{$MRN}"
ParameterName="Gender" ParameterValue="{$Gender}"
Operation="{$Operation}"
OverwriteExistingData="{$Overwrite}"
/>
<PatientDataRecord
MedicalRecordNumber="{$MRN}"
ParameterName="Race_7_Groups" ParameterValue="{$Race}"
Operation="{$Operation}"
OverwriteExistingData="{$Overwrite}"
/>
</eCliPSEDataIntegrationServiceRequest>
</xsl:template>
</xsl:stylesheet>
感谢您的反馈和建议。
此版本处理案例转换/比较以及以我需要的格式格式化bday。
我喜欢AVT语法来简化代码并删除我正在做的“手动格式化” - 感谢这些提示!
答案 2 :(得分:0)
这应该让你开始走正确的道路:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="PATIENTLIST">
<xsl:for-each select="PATIENT">
<eCliPSEDataIntegrationServiceRequest>
<xsl:attribute name="xmlns">
http://iocent.com/eCliPSEDataIntegrationServiceRequest.xsd
</xsl:attribute>
<PatientIdentifierRecord>
<xsl:attribute name="MedicalRecordNumber">
<xsl:value-of select="@ID"/>
</xsl:attribute>
...
<xsl:for-each select="MEDICALRECORDNUMBER">
<xsl:attribute name="MedicalRecordNumber">
<xsl:value-of select="@ID"/>
</xsl:attribute>
...
</xsl:for-each>
</PatientIdentifierRecord>
</eCliPSEDataIntegrationServiceRequest>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
您可能需要一些硬编码<xsl:if test="SEX='MALE'">1</xsl:if>
语句来执行“枚举”切换
答案 3 :(得分:0)
只是一些提示。
使用AVT语法简化代码。例如:
<PatientIdentifierRecord
MedicalRecordNumber="{$MRN}"
LastName="{PATIENTLIST/PATIENT/LASTNAME}"
...
/>
对于换行,请使用ISO-8859-1字符集中的代码:
<xsl:variable name="lf" select="' '"/>
有关日期时间,请参阅此topic并查看解析器文档。
如果您需要更改日期格式,请使用substring()
和concat()
功能。检查this similar topic。
您似乎正在使用换行来缩进代码。对于这项工作,您有一个正确的指令(根据您的解析器可能支持):
<xsl:output indent="yes"/>