Question

想象一下这个字符串：

    _  _     _  _  _  _  _
  | _| _||_||_ |_   ||_||_|
  ||_  _|  | _||_|  ||_| _|

分割此字符串的最简单/最好的方法是什么，以便每个数字都可以自己处理？

我在考虑像

这样的东西

public string[] SplitIntoNumbers(string input)

结果如

["     |  |", " _  _||_ ", " _  _| _|", ...]

有什么想法吗？

修改
因为想要更多的信息 - 问题来自BankOCR - kata over CodingDojo。我意识到有多种方法可以“完成工作” - 解决方案，但我觉得必须有一种更''花哨'的解决方法。一些类似于clojure的东西。

Answer 1

你问：

分割此字符串的最简单/最好的方法是什么，以便每个数字都可以自己处理？

......我认为你可能会从一个OO的角度来看待这个问题。你所说的实际上是一个'字体'而不是一个字符集。我坦率地将逻辑包装成一个单独的类，并完全按照你的帖子定义字符数据。它易于查看，编辑和维护。

如果你的最终目标只是渲染，或者它正在解析，我从原始帖子中无法理解。无论如何，我不能只停留在数字上;）

    static void Main()
    {
        LineBuffers lb = new LineBuffers(80 / 3);
        lb.Write(0, "-_ 1234567890");
        Console.WriteLine(String.Join(Environment.NewLine, lb.Lines.ToArray()));
        Console.WriteLine();
        Console.WriteLine(lb.ReadLine());

        lb.Clear();
        lb.Write(0, "abcdefghijklm");
        Console.WriteLine(String.Join(Environment.NewLine, lb.Lines.ToArray()));
        Console.WriteLine();
        Console.WriteLine(lb.ReadLine());

        lb.Clear();
        lb.Write(0, "nopqrstuvwxyz");
        Console.WriteLine(String.Join(Environment.NewLine, lb.Lines.ToArray()));
        Console.WriteLine();
        Console.WriteLine(lb.ReadLine());

        lb = new LineBuffers(" _     _  _  _ ", "|_| _ |  |_ |_|", @"|\ |_||_-|_ |\ ");
        Console.WriteLine(lb.ReadLine());

    }

    public class LineBuffers
    {
        private static string Characters = " -0123456789_abcdefghijklmnopqrstuvwxyz";
        private static readonly string[] Format =
            (
            @".   .   . _ .   . _ . _ .   . _ . _ . _ . _ . _ .   . _ .   . _ .   . _ . _ . _ .   . _ .  _.   .   .   .   .   . _ . _ . _ . _ .___.   .   .   .   .   .__ ." + "\n" +
            @".   . _ .| |.  |. _|. _|.|_|.|_ .|_ .  |.|_|.|_|.   .|_|.|_ .|  . _|.|_ .|_ .|  .|_|. | .  |.|/ .|  .|\|.|\|. _ .|_|.|_|.|_|./_ . | .| |.| |.|||. \/. \/. / ." + "\n" +
            @".   .   .|_|.  |.|_ . _|.  |. _|.|_|.  |.|_|. _|.___.| |.|_|.|_ .|_|.|_ .|  .|_-.| |. | . _|.|\ .|_ .|||.| |.|_|.|  .  |.|\ . _/. | .|_|.|/ .|/|. /\. | ./_ ."
            ).Split('\n');

        private readonly char[][] _lines;

        public LineBuffers(int charWidth)
        {
            _lines = new char[3][] {new char[charWidth*3], new char[charWidth*3], new char[charWidth*3]};
            Clear();
        }

        public LineBuffers(string line1, string line2, string line3) 
            : this(line1.ToCharArray(), line2.ToCharArray(), line3.ToCharArray()) { }

        public LineBuffers(char[] line1, char[] line2, char[] line3)
        {
            if (line1 == null || line2 == null || line3 == null 
                || line1.Length != line2.Length || line2.Length != line3.Length)
                throw new ArgumentException();

            _lines = new char[3][] {
                line1, line2, line3
            };
        }

        public int Count { get { return _lines[0].Length / 3; } }
        public IEnumerable<string> Lines { get { return _lines.Select(chars => new String(chars)); } }

        public void Clear()
        {
            for (int i = 0; i < Count; i++)
                Write(i, ' ');
        }

        public void Write(int position, IEnumerable<Char> character)
        { foreach (char ch in character) Write(position++, ch); }

        public void Write(int position, Char character)
        {
            int charIx = Characters.IndexOf(Char.ToLower(character));
            if (charIx < 0)
                throw new ArgumentOutOfRangeException("character");
            if (position >= Count)
                throw new ArgumentOutOfRangeException("position");

            int offset = charIx*4 + 1;
            for(int line=0; line <3; line++)
                Array.Copy(Format[line].ToCharArray(offset, 3), 0, _lines[line], position * 3, 3);
        }

        public Char Read(int position)
        {
            if (position >= Count)
                throw new ArgumentOutOfRangeException("position");

            IEnumerable<int> found = Find(Format[0], _lines[0], position*3)
                .Intersect(Find(Format[1], _lines[1], position*3))
                .Intersect(Find(Format[2], _lines[2], position*3));

            int[] result = found.ToArray();
            if (result.Length != 1)
                throw new FormatException();
            return Characters[result[0]];
        }

        IEnumerable<int> Find(string findIn, char[] text, int charIx)
        {
            for(int i=1; i < findIn.Length; i += 4)
            {
                if (findIn[i] == text[charIx] && findIn[i + 1] == text[charIx + 1] && findIn[i + 2] == text[charIx + 2])
                    yield return i/4;
            }
        }

        public string ReadLine()
        {
            char[] text = new char[Count];
            for (int ix = 0; ix < Count; ix++)
                text[ix] = Read(ix);
            return new String(text);
        }
    }

前面的程序输出以下文字：

             _  _     _  _  _  _  _  _
 _         | _| _||_||_ |_   ||_||_|| |
   ___     ||_  _|  | _||_|  ||_| _||_|

-_ 1234567890
 _     _     _  _  _     _   _
|_||_ |   _||_ |_ |  |_| |   ||/ |  |\|
| ||_||_ |_||_ |  |_-| | |  _||\ |_ |||

abcdefghijklm
       _  _  _  _ ___               __
|\| _ |_||_||_|/_  | | || |||| \/ \/ /
| ||_||    ||\  _/ | |_||/ |/| /\ | /_

nopqrstuvwxyz

Answer 2

直截了当：

    public static string[] SplitIntoNumbers(string input)
    {
        List<string> result = new List<string>();
        string[] subStrs = input.Split(new char[] { '\r', '\n' }, 3, StringSplitOptions.RemoveEmptyEntries);
        for (int it = 0; it < subStrs[0].Length; it += 3)
        {
            result.Add(subStrs[0].Substring(it, 3)
                + subStrs[1].Substring(it, 3)
                + subStrs[2].Substring(it, 3));
        }
        return result.ToArray();
    }

（编辑）我使用的字符串是：

    static string str =
@"
    _  _     _  _  _  _  _ 
  | _| _||_||_ |_   ||_||_|
  ||_  _|  | _||_|  ||_| _|";

Answer 3

我会使用正则表达式来构建一个匹配列表，其模式与此类似

(.{3})

这会将输入分成3x1匹配的块，并且取决于你有多少匹配将确定数字。例如

    _  _     _  _  _  _  _
  | _| _||_||_ |_   ||_||_|
  ||_  _|  | _||_|  ||_| _|

将产生27个3x1段的匹配，并且因为每个数字是3行高，所以你可以采用27/3 = 9个单独的数字。然后你只需要遍历正则表达式匹配并将它们组合成你想要的输出。

void Main()
{
    string input = "    _  _     _  _  _  _  _ \r\n  | _| _||_||_ |_   ||_||_|\r\n  ||_  _|  | _||_|  ||_| _|";

    string[] result = SplitIntoNumbers(input);
}

public string[] SplitIntoNumbers(string input)
{
    List<string> results = new List<string>();

    Regex rx = new Regex("(.{3})");
    MatchCollection matches = rx.Matches(input);
    int totalNumbers = matches.Count / 3;

    for(int i = 0; i < totalNumbers; i++)
    {
        string s = string.Concat(matches[i].Value, matches[i + totalNumbers].Value, matches[i + (totalNumbers * 2)].Value);

        results.Add(s);
    }

    return results.ToArray();
}

Answer 4

假设你想保留输入的字符串数组，我们可以非常简单地循环通过一次拉3个字符的行。

    var numbers = new[]
                    {
                        "    _  _     _  _  _  _  _ ",
                        "  | _| _||_||_ |_   ||_||_|",
                        "  ||_  _|  | _||_|  ||_| _|"
                    };

            // just in case length is off on one, don't want to crash
    var length = numbers.Min(line => line.Length);
    var results = new List<string>();

            // go by groups of three
    for (int i = 0; i < length; i += 3)
    {
        var builder = new StringBuilder();
        for (int j = 0; j < numbers.Length; j++)
        {
            builder.Append(numbers[j].Substring(i, 3));
        }

        results.Add(builder.ToString());
    }

            // print the results
    foreach (var digit in results)
    {
        Console.WriteLine(digit);
    }

Answer 5

扩展方法怎么样：

    public static string[] SplitIntoNumbers(this string str)
    {
        var lines = str.Split(new[] { '\r', '\n' }, StringSplitOptions.RemoveEmptyEntries);
        var columns = lines
            .Select(x => x.InSetsOf(3).Select(y => new string(y.ToArray())).ToList())
            .ToList();
        var numbers = Enumerable.Range(0, columns[0].Count)
            .Select(x => columns[0][x] + columns[1][x] + columns[2][x])
            .ToArray();
        return numbers;
    }

假设a compatible implementation of InSetsOf()可用。

用法：

        var result = input.SplitIntoNumbers();

一次读取一个字符串，3x3个字符

5 个答案: