我有一些简单的SOAP客户端从WSDL获取数据并显示它。
<?php
//Data, connection, auth
$dataFromTheForm = $_POST['fieldName']; // request data from the form
$soapUrl = "https://connecting.website.com/soap.asmx?op=DoSomething"; // asmx URL of WSDL
$soapUser = "username"; // username
$soapPassword = "password; // password
// xml post structure
$xml_post_string = '<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<GetItemPrice xmlns="http://connecting.website.com/WSDL_Service"> // xmlns value to be set to your's WSDL URL
<PRICE>'.$dataFromTheForm.'</PRICE> // data from the form, e.g. some ID number
</GetItemPrice >
</soap:Body>
</soap:Envelope>';
$headers = array(
"Content-type: text/xml;charset=\"utf-8\"",
"Accept: text/xml",
"Cache-Control: no-cache",
"Pragma: no-cache",
"SOAPAction: http://connecting.website.com/WSDL_Service/GetPrice", // your op URL
"Content-length: ".strlen($xml_post_string),
);
$url = $soapUrl;
// PHP cURL for https connection with auth
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, $soapUser.":".$soapPassword); // username and password - declared at the top of the doc
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $soapUrl); // asmx URL of WSDL - declared at the top of the doc
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
// converting
$response = curl_exec($ch);
curl_close($ch);
// converting
$response1 = str_replace("<soap:Body>","",$response);
$response2 = str_replace("</soap:Body>","",$response1);
// convertingc to XML
$parser = simplexml_load_string($response2);
?>
一切正常 - 当WSDL正常工作时。
但是,当WSDL失败(服务器上的运行时错误)时,我的网站在第152行抛出了数百个警告:
$parser = simplexml_load_string($response2);
如何检测WSDL是否返回了无效的XML(html错误消息)并在此基础上显示简单的错误消息?
答案 0 :(得分:2)
提示 使用libxml_use_internal_errors()来抑制所有XML错误,然后使用libxml_get_errors()来迭代它们。
<小时/> UPDATE:
对于这种情况,示例如下:
libxml_use_internal_errors(true); //enable error handling
$parser = simplexml_load_string($output2);
if(!$parser){ // if $parser is not valid XML response
echo '<p>Sorry. This service is currently unavailable. Please try again later.</p>';
} else {
//if $parser is valid XML response, do something
}
答案 1 :(得分:1)
只需检查标题(内容类型)或简单检查$ response是否以<?xml
开头。