这是我的代码：
<?php
require_once '../../../jq-config.php';
// include the jqGrid Class
require_once ABSPATH."php/jqGrid.php";
// include the driver class
require_once ABSPATH."php/jqGridPdo.php";
// Connection to the server
$conn = new PDO(DB_DSN,DB_USER,DB_PASSWORD);
/ / Tell the db that we use utf-8
$conn->query("SET NAMES utf8");
// Create the jqGrid instance
$grid = new jqGridRender($conn);
// Write the SQL Query
$grid->SelectCommand = 'SELECT p.product_id, p.product_title, p.product_image1_t2, pc.product_cat_name, b.brand_name FROM ' . DB_PRODUCTS .' p INNER JOIN ' . DB_PRODUCT_CATS . ' pc ON p.product_cat_id=pc.product_cat_id LEFT JOIN ' . DB_BRANDS . ' b ON b.brand_id=pc.product_cat_brand_id';
// set the ouput format to json
$grid->dataType = 'json';
// Let the grid create the model from SQL query
$grid->setColModel();
// Set the url from where we obtain the data
$grid->setUrl('grid.php');
// Set alternate background using altRows property
$grid->setGridOptions(array(
"rowNum"=>10,
"sortname"=>"product_id",
"rowList"=>array(10,20,50),
"height"=>'auto',
"grouping"=>true,
"groupingView"=>array(
"groupField" => array('brand_name'),
"groupColumnShow" => array(true),
"groupText" =>array('<b>{0}</b>'),
"groupDataSorted" => true
)
));
// Change some property of the field(s)
$grid->setColProperty("product_id", array("label"=>"NO", "width"=>60));
$grid->setColProperty("brand_name", array("label"=>"BRAND"));
$grid->setColProperty("product_title", array("label"=>"PRODUCT NAME"));
$grid->setColProperty("product_cat_name", array("label"=>"CATEGORY"));
$grid->setColProperty("product_image1_t2", array("label"=>"PRODUCT PHOTO"));
// Enjoy
$grid->renderGrid('#grid','#pager',true, null, null, true,true);
$conn = null;
?>
所以，我成功获取了我的整个数据但是，当我调用此文件时，我在“product_image1_t2”（PRODUCT PHOTO）网格中看到了我的文件名称，例如： “image_file.jpg”。我希望将图像显示为显示的内容
<img src="myfile.jpg" alt="my_file.jpg" />
已经检查手册但不明白，所以我是jquery的新手......
你可以帮助我这个例子怎么做？ 在这里你可以看到当前的结果：
