Question

我正在尝试搜索我的orderid，这是我到目前为止的代码：

<?php
$file = 'order.dat';
$searchfor = '177';

// the following line prevents the browser from parsing this as HTML.
header('Content-Type: text/plain');

// get the file contents, assuming the file to be readable (and exist)
$contents = file_get_contents($file);
// escape special characters in the query
$pattern = preg_quote($searchfor, '/');
// finalise the regular expression, matching the whole line
$pattern = "/^.*$pattern.*\$/m";
// search, and store all matching occurences in $matches
if(preg_match_all($pattern, $contents, $matches)){
   echo "Found matches:\n";
   echo implode("\n", $matches[0]);
}
else{
   echo "No matches found";
}

现在例如我的order.dat文件包含数据

175|RC456456456|54156456465|109$

176|RC456456456|54156456465|177$

177|RC456456456|54156456465|129$

178|RC456456456|54156456465|129$

现在当我搜索177时，我得到这样的结果： -

Found matches:
176|RC456456456|54156456465|177$
177|RC456456456|54156456465|129$

但我想在177搜索我的第一个字符串

我想要这样的结果，它只匹配我的第一个字符串而不是所有4个变量

177|RC456456456|54156456465|129$

Answer 1

您希望仅匹配以 177开头的字符串 。如果是，您可以将正则表达式更改为：

$pattern = "/^$pattern.*$/m";

Answer 2

$pattern = "/^$pattern/m"; // your string starts (^) with $pattern (177) 
                           // and we dont care what it ends with

Answer 3

http://sandbox.phpcode.eu/g/3fff8.php

$pattern = "/^$pattern.*?\$/m";

而不是

$pattern = "/^.*|$pattern.*\$/m";

从dat文件中搜索php

3 个答案: