Question

你能帮帮我们吗？因为我在listview的顶部制作了一个edittext，用于按时过滤数据，但是当它被过滤后，第一个索引总是0 ...因此我过滤了第50行，我没有得到它的父ID

public class Moshimoshi extends Activity {
/** Called when the activity is first created. */
private ListView lv;
private EditText ed;
ArrayAdapter<String> adapterForListview;
ContentResolver cr;
private long[] item_id;
private String lv_arr[];
int textlength = 0;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    cr = getContentResolver();
    lv = (ListView) findViewById(R.id.listView1);
    ed = (EditText) findViewById(R.id.editText1);
    adapterForListview = new ArrayAdapter<String>(this,
            android.R.layout.simple_list_item_1);
    viewData();
    lv.setAdapter(new ArrayAdapter<String>(this,
            android.R.layout.simple_list_item_1, lv_arr));
    lv.setOnItemClickListener(new OnItemClickListener() {
        public void onItemClick(AdapterView<?> a, View v, int position,
                long id) {

            Log.i(String.valueOf(id), String.valueOf(item_id[(int)   id]));
            Intent info = new Intent(getApplicationContext(), Info.class);
            int rowid = (int) item_id[(int) id];
            info.putExtra("key", rowid);

            // update.addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY);
            //
            startActivity(info);
        }
    });
    ed.addTextChangedListener(new TextWatcher() {

        public void afterTextChanged(Editable s) {
        }

        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
        }

        public void onTextChanged(CharSequence s, int start, int before,
                int count) {

            textlength = ed.getText().length();
            adapterForListview.clear();
            for (int i = 0; i < lv_arr.length; i++) {
                if (textlength <= lv_arr[i].length()) {
                    if (ed.getText()
                            .toString()
                            .equalsIgnoreCase(
                                    (String) lv_arr[i].subSequence(0,
                                                 textlength))) {
                        adapterForListview.add(lv_arr[i]);
                    }
                }
            }

            lv.setAdapter(adapterForListview);
        }
    });

}

public void viewData() {
    // Cursor cursor = conRes.query(CONTENT_URI_Applicant, new String[] {
    // _ID,
    // FName, LName }, null, null, FName);
    Cursor cursor = cr.query(CONTENT_URI_rawquery, null,
            "Select _id,FName,LName FROM Applicant", null, null);
    startManagingCursor(cursor);
    while (cursor.moveToNext()) {

        // Could use getColumnIndexOrThrow() to get indexes
        adapterForListview.add(cursor.getString(cursor
                .getColumnIndex(FName))
                + "         "
                + cursor.getString(cursor.getColumnIndex(LName)));
        // i++;
        // Log.i("Id", String.valueOf(item_id[i]));
    }

    item_id = new long[cursor.getCount()];
    lv_arr = new String[cursor.getCount()];
    int i = 0;
    for (cursor.moveToFirst(); !cursor.isAfterLast(); cursor.moveToNext()) {
        item_id[i] = cursor.getLong(cursor.getColumnIndex(_ID));
        lv_arr[i] = cursor.getString(cursor.getColumnIndex(FName)) + " "
                + cursor.getString(cursor.getColumnIndex(LName));
        Log.v("ite_id:" + i, "" + item_id[i]);
        i++;

    }
    cursor.close();
}
}

Answer 1

尝试使用SimpleCursorAdapter这样的

String[] from = new String[] { "YourDatabseColumnName" };           
int[] to = new int[] {android.R.id.text1};          
SimpleCursorAdapter playerAdapter = new SimpleCursorAdapter(context, android.R.layout.simple_list_item_single_choice , cursor, from, to);

虽然过滤只是使用类似这样的东西

public void onTextChanged(CharSequence s, int start, int before, int count)
{
    playerAdapter.getFilter().filter(s);
}

A good tutorial here关于使用sqlite和显示数据。

Answer 2

也许是为了答案迟到，但它可以帮助其他人。

我遇到了同样的问题。解决方案是您还必须在进行过滤时更新列表中的项目。例如，当列表被过滤后你在ListView中得到三个项目时，你的项目列表（这里我指的是ArrayList或其他东西，而不是与ListView混淆）也应该只有三个项目，因此ID总是同步的。

我希望它有所帮助。

如何过滤列表视图中的项目ID？ Android的

2 个答案: