Question

可能重复：
echoing in the view page

我试图从我的桌子回复我的字段。但是当我运行代码时显示以下错误

消息：尝试获取非对象的属性

文件名：views / details_view.php

行号：6

我的控制器的功能

    function index()
{

    //using model
    $data['list'] = $this->Rfetch_model->getdata();
    $this->load->view('Rfetch_view', $data);
}

function get_by_id($id = 0){

    $data['info'] = $this->Rfetch_model->getdata_by_id($id);


    $this->load->view('details_view', $data);
}

我的模特的功能

function getdata () {
        $this->db->select ('subject, id, problem'); // field name
        $sql = $this->db->get('info'); // table name
        if ($sql->num_rows () >0) {
            foreach($sql->result() as $row) {
            $data[$row->id] = $row->subject;
            }
            return $data;
         }
    }

    function getdata_by_id($id = 0){
        $this->db->where('id',$id);

        $sql = $this->db->get('info');

        return $sql->result();
    }

}

我的观点（details_view）：

<?php echo $info->problem;  ?>

当我打印info.it时给出以下输出

Array    
(
    [0] => stdClass Object

(

  [id] => 2

            [address] => some
            [area] => some
            [lat] => 1223
            [lng] => 2133
            [subject] => some
            [problem] =>problem
            [image] => 
            [time] => 2011-08-12 01:09:44
            [register_id] => 1
            [category_id] => 2
            [city_city_id] => 1
            [status_status_id] => 0
        )

)

Answer 1

试试这个：

<?php echo $info[0]->problem;  ?>

Answer 2

在getdata_by_id，您将返回$sql->result()。这给出了一个对象数组。您可以使用$sql->row()返回该行的对象。

在视图页面中回显

2 个答案: