我的查询返回account.name,account.account和account.parentaccountid。
我正在使用Silverlight和CRM2011。
现在我无法找到如何从parentaccountid属性中提取值。
我的VS项目中包含silverlightextensionmethods.cs文件,我正在使用GetAttributeValue<Guid>("parentaccountid")
从parentaccountid
获取值。
返回的值为空。
我可以获得任何其他属性值,但是帐户中的parentaccountid和联系中的parentcustomerid使我的生活变得非常困难。
代码: 首先我创建QUERYEXPRESSION:
string temp="name;accountid;parentaccountid";
string[] fields = temp.Split(';');
QueryExpression query = new QueryExpression()
{
EntityName = entity,
ColumnSet = new ColumnSet { Columns = new System.Collections.ObjectModel.ObservableCollection<string>(fields) },
Criteria = new FilterExpression
{
FilterOperator = LogicalOperator.And,
Conditions =
{
new ConditionExpression
{
AttributeName = parentidfield,
Operator = ConditionOperator.Equal,
Values = { id }
}
}
}
};
OrganizationRequest req = new OrganizationRequest();
req.RequestName = "RetrieveMultiple";
req["Query"] = query;
service.BeginExecute(req, new AsyncCallback(GetChildren_ExecuteCallBack), service);
下一步我打算阅读价值回复
void GetChildren_ExecuteCallBack(IAsyncResult childresult)
{
List<TreeRecord> listc = new List<TreeRecord>();
try
{
OrganizationResponse childresponse = ((IOrganizationService)childresult.AsyncState).EndExecute(childresult);
EntityCollection childresults = (EntityCollection)childresponse["EntityCollection"];
if (childresults.Entities.Count > 0)
{
TreeConfig sitm = new TreeConfig();
string sdisplay = "";
string[] fields = "".Split(';');
string sid = "";
string pid = "";
foreach (Entity childentity in childresults.Entities)
{
foreach (TreeConfig sitem in Configs)
{
if (sitem.EntityName == childentity.LogicalName)
{
sitm = sitem;
}
}
TreeRecord childitem = new TreeRecord();
string sValue = "";
sdisplay = "name;accountid;parentaccountid";
fields = sdisplay.Split(';');
sid = "accountid";
pid = "parentaccountid";
int i = sdisplay.Split(';').Length;
for (int j = 0; j < i; j++)
{
try { sValue += childentity.GetAttributeValue<string>(fields[j]) + " "; }
catch (Exception ex)
{
//s = "sValue haku: " + ex.Message.ToString();
//this.ReportMessage(s.ToString());
}
}
childitem.Name = sValue;
childitem.EntityName = childentity.LogicalName;
childitem.Level = sitm.Level;
childitem.ParentEntityName = sitm.EntityName;
childitem.Color = sitm.Color;
childitem.RecordId = childentity.GetEntityId<Guid>(sid);
try { childitem.ParentId = childentity.GetAttributeValue<Guid>(pid); }
catch
{
//sb.AppendLine("guid: parentid tietoa ei löydy");
//this.ReportMessage(sb.ToString());
}
listc.Add(childitem);
}
}
}
答案 0 :(得分:3)
而不是
childentity.GetAttributeValue<Guid>(pid)
使用
childentity.GetAttributeValue<EntityReference>(pid)