我正在尝试根据定义的模式将对象中的数据编组到xml文件中。但是,当我打印出xml文件时,我在xml标签上收到了额外的注释。有没有办法摆脱额外的命名空间注释(即ns2)
这是我从编组中收到的xml示例。
<?xml version="1.0" encoding="UTF-8" standalone="yes">
<root xmlns:ns2="http://www.something.com/something">
<ns2:food>steak</ns2:food>
<ns2:beverage>water</ns2:beverage>
</root>
我想要的是这样的:
<?xml version="1.0" encoding="UTF-8" standalone="yes">
<root xmlns="http://www.something.com/something">
<food>steak</food>
<beverage>water</beverage>
</root>
这是我的Java代码正在做的事情:
JAXBContext context = JAXBContext.newInstance("com.schema");
JAXBElement<FoodSchema> element = new JAXBElement<FoodSchema>
(new QName("FoodSchema"), Food.class, foodSchema);
Marshaller marshaller = context.createMarshaller();
OutputStream os = new FileOutputStream(object.getFilePath());
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(element, os);
非常感谢任何帮助!谢谢!
答案 0 :(得分:16)
通过向用于构造JAXB元素的QName
添加名称空间URI(“http://www.something.com/something”),并利用包级别@XmlSchema
注释将获得您正在寻找的命名空间限定:
<强>包信息强>
@XmlSchema(
namespace="http://www.something.com/something",
elementFormDefault=XmlNsForm.QUALIFIED)
package forum7014746;
import javax.xml.bind.annotation.*;
<强>食品强>
package forum7014746;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Food {
private String food;
private String beverage;
public String getFood() {
return food;
}
public void setFood(String food) {
this.food = food;
}
public String getBeverage() {
return beverage;
}
public void setBeverage(String beverage) {
this.beverage = beverage;
}
}
<强>演示强>
package forum7014746;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.Marshaller;
import javax.xml.namespace.QName;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jaxbContext = JAXBContext.newInstance(Food.class);
Food foodSchema = new Food();
foodSchema.setFood("steak");
foodSchema.setBeverage("water");
JAXBElement<Food> element = new JAXBElement<Food> (new QName("http://www.something.com/something","FoodSchema"), Food.class, foodSchema);
Marshaller marshaller = jaxbContext.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(element, System.out);
}
}
<强>输出强>
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<FoodSchema xmlns="http://www.something.com/something">
<beverage>water</beverage>
<food>steak</food>
</FoodSchema>
答案 1 :(得分:4)
添加到xsd架构定义 elementFormDefault 和 attributeFormDefault :
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" ...
elementFormDefault="qualified" attributeFormDefault="unqualified" ... >
答案 2 :(得分:3)
谢谢你的回答。只是给出示例代码 之前:
marshaller.marshal(new JAXBElement(new QName(**""**,"Document"),Document.class,swiftDoc), sw);
之后:
marshaller.marshal(new JAXBElement(new QName(**"http://www.w3.org/2001/XMLSchema**","Document"),Document.class,swiftDoc), sw);
并删除了额外的“ns:”。