Question

不确定如何在这个标题上标出标题！

我有以下数据：

IF OBJECT_ID ('tempdb..#data') IS NOT NULL DROP TABLE #data
CREATE TABLE #data
(
id UNIQUEIDENTIFIER
,reference NVARCHAR(30)
,start_date DATETIME
,end_date DATETIME
,lapse_date DATETIME
,value_received DECIMAL(18,3)
)

INSERT INTO #data VALUES ('BE91B9C1-C02F-46F7-9B63-4D0B25D9BA2F','168780','2006-05-01 00:00:00.000',NULL,'2011-09-27 00:00:00.000',537.42)
INSERT INTO #data VALUES ('B538F123-C839-447A-B300-5D16EACF4560','320858','2011-08-08 00:00:00.000',NULL,NULL,0)
INSERT INTO #data VALUES ('1922465D-2A55-434D-BAAA-8E15D681CF12','306597','2011-04-08 00:00:00.000','2011-06-22 13:14:40.083','2011-08-07 00:00:00.000',12)
INSERT INTO #data VALUES ('7DF8FBCC-B490-4892-BDC5-8FD2D73B0323','321461','2011-07-01 00:00:00.000',NULL,'2011-09-25 00:00:00.000',8.44)
INSERT INTO #data VALUES ('1EC2E754-F325-4313-BDFC-9010E255F6FE','74215','2000-10-31 00:00:00.000',NULL,'2011-08-30 00:00:00.000',258)
INSERT INTO #data VALUES ('9E59B09C-0198-48AC-8EEC-A0D76CEA9385','169194','2008-06-25 00:00:00.000',NULL,'2011-09-25 00:00:00.000',1766.4)
INSERT INTO #data VALUES ('97CF6C0F-324A-49A6-B9D8-AC848A1F821A','288039','2010-09-01 00:00:00.000','2011-07-29 00:00:00.000','2011-08-21 00:00:00.000',55)
INSERT INTO #data VALUES ('97CF6C0F-324A-49A6-B9D8-AC848A1F821A','324423','2011-08-01 00:00:00.000',NULL,'2011-09-25 00:00:00.000',5)
INSERT INTO #data VALUES ('D5E5197A-E8E1-468C-9991-C8712224C2BF','323395','2011-08-25 00:00:00.000',NULL,NULL,0)
INSERT INTO #data VALUES ('0EC4976C-16B9-4C99-BD07-D0CBDF014D32','323741','2011-08-25 00:00:00.000',NULL,NULL,0)

我希望能够根据以下标准将所有引用分组为“活动”，“已失效”或“新”类别：

Active的开始日期小于参考月的最后日期，上个月最后一天之后的失效日期以及value_received＆gt; 0;
New的开始日期属于参考月份;
Lapsed的失效日期属于参考月份。

然后将这些定义应用于滚动13个月的每个参考（因此从现在回溯到2010年7月），以便每个月我可以看到有多少参考文献属于每个组。

我可以使用以下内容为当月定义：

select 
id
,reference
,start_date
,end_date
,lapse_date 
,value_received
,CASE   WHEN start_date < DATEADD(month,DATEPART(Month,GETDATE()) + 1,DATEADD(year,DATEPART(year,GETDATE())-1900,0)) --next month start date
        AND lapse_date > DATEADD(ms,-3,DATEADD(mm,DATEDIFF(mm,0,GETDATE())+1,0)) --last day of current month
        AND value_received > 0
        THEN 'Active'
        WHEN lapse_date < DATEADD(month,DATEPART(Month,GETDATE()) + 1,DATEADD(year,DATEPART(year,GETDATE())-1900,0)) --next month start
            AND lapse_date > DATEADD(ms,-3,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)) --last day of prior month
        THEN 'lapse'
        WHEN start_date < DATEADD(month,DATEPART(Month,GETDATE()) + 1,DATEADD(year,DATEPART(year,GETDATE())-1900,0)) --next month start date
        AND start_date > DATEADD(ms,-3,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)) --last day of prior month
        THEN 'New'
        ELSE 'Not applicable'
 END AS [type]
from #data

但我看不到一个好的/有效的方法（除了重复这个查询13次并结合结果，我知道这很糟糕）

这是使用当前月份作为锚点并使用递归的情况（如果是这样，一些指针会非常受欢迎）？

任何最受赞赏的帮助：）

*已修改为包含实际解决方案*

如果对任何人感兴趣，这是我使用的最终查询：

;WITH Months as 
(
SELECT DATEADD(ms,-3,DATEADD(mm,DATEDIFF(mm,0,GETDATE())+1,0)) as month_end
,0 AS level
UNION ALL     
SELECT DATEADD(month, -1, month_end)as month_end
,level + 1 FROM Months
WHERE level < 13 
) 
SELECT 
DATENAME(Month,month_end) + ' ' + DATENAME(YEAR,month_end) as date
,SUM(CASE WHEN start_date <= month_end
        AND Month(start_date) <> MONTH(Month_end)
        AND lapse_date > Month_end 
 THEN 1 ELSE 0 END) AS Active
,SUM(CASE WHEN start_date <= Month_end 
        AND DATENAME(MONTH,start_date) + ' ' + DATENAME(YEAR,start_date) = 
        DATENAME(MONTH,month_end) + ' ' + DATENAME(YEAR,month_end)
THEN 1 ELSE 0 END) AS New
,SUM(CASE WHEN lapse_date <= Month_end 
        AND Month(lapse_date) = MONTH(Month_end)
THEN 1 ELSE 0 END) AS lapse
FROM #data
CROSS JOIN Months
WHERE id IS NOT NULL
AND start_date IS NOT NULL
GROUP BY DATENAME(Month,month_end)  + ' ' + DATENAME(YEAR,month_end) 
ORDER by MAX(level) ASC

Answer 1

这里不需要“真正的”递归CTE。您可以使用一个月份参考：

;WITH Months
as
(
    SELECT DATEADD(day, -DATEPART(day, GETDATE())+1, GETDATE()) as 'MonthStart'
    UNION ALL
    SELECT DATEADD(month, -1, MonthStart) as 'MonthStart'
    FROM Months
)

然后，您可以在上述查询中JOIN到SELECT TOP 13 * FROM Months。

我不会尝试解析您的所有CASE语句，但基本上您可以在日期和GROUP BY字段上使用MonthStart，例如：

GROUP BY Datepart(year, monthstart), Datepart(month, monthstart)

按月汇总。最简单的方法是将所有选项（有效，失效等）作为列，并使用SUM(CASE WHEN ... THEN 1 ELSE 0 END)计算每个选项，因为使用GROUP BY会更容易。

Answer 2

您可以通过递归CTE交叉加入您的请求，这是一个好主意。

WITH thirteenMonthBack(myDate, level) as
(
   SELECT GETDATE() as myDate, 0 as level
   UNION ALL
   SELECT DATEADD(month, -1, myDate), level + 1
   FROM thirteenMonthBack
   WHERE level < 13
)
SELECT xxx
FROM youQuery
   CROSS JOIN thirteenMonthBack

Answer 3

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                                  (textView.textContainerInset.top + textView.textContainerInset.bottom));
CGSize targetSize = CGSizeMake((300.0 - reservedSpace.width), CGFLOAT_MAX);
NSString* message = @"The Internet connection appears to be offline.";

NSStringDrawingContext* context = [[NSStringDrawingContext alloc] init];
CGSize boundingBox = [message boundingRectWithSize:targetSize
                                              options:NSStringDrawingUsesLineFragmentOrigin
                                           attributes:@{NSFontAttributeName:FontOpenSanWithSize(14)}
                                              context:context].size;

CGSize size = CGSizeMake(ceil(boundingBox.width),
                         (ceil(boundingBox.height) + reservedSpace.height));

使用日期范围可能的递归CTE查询

3 个答案: