所以我有一个提供输出的代码,我需要做的是在逗号之间拉出信息,将它们分配给一个在调用时动态变化的变量......这是我的代码:
import re
data_directory = 'Z:/Blender_Roto/'
data_file = 'diving_board.shape4ae'
fullpath = data_directory + data_file
print("====init=====")
file = open(fullpath)
for line in file:
current_line = line
# massive room for optimized code here.
# this assumes the last element of the line containing the words
# "Units Per Second" is the number we are looking for.
# this is a non float number, generally.
if current_line.find("Units Per Second") != -1:
fps = line_split = float(current_line.split()[-1])
print("Frames Per Second:", fps)
# source dimensions
if current_line.find("Source Width") != -1:
source_width = line_split = int(current_line.split()[-1])
print("Source Width:", source_width)
if current_line.find("Source Height") != -1:
source_height = line_split = int(current_line.split()[-1])
print("Source Height:", source_height)
# aspect ratios
if current_line.find("Source Pixel Aspect Ratio") != -1:
source_px_aspect = line_split = int(current_line.split()[-1])
print("Source Pixel Aspect Ratio:", source_px_aspect)
if current_line.find("Comp Pixel Aspect Ratio") != -1:
comp_aspect = line_split = int(current_line.split()[-1])
print("Comp Pixel Aspect Ratio:", comp_aspect)
# assumption, ae file can contain multiple mocha shapes.
# without knowing the exact format i will limit the script
# to deal with one mocha shape being animated N frames.
# this gathers the shape details, and frame number but does not
# include error checking yet.
if current_line.find("XSpline") != -1:
# record the frame number.
frame = re.search("\s*(\d*)\s*XSpline", current_line)
if frame.group(1) != None:
frame = frame.group(1)
print("frame:", frame)
# pick part the part of the line that deals with geometry
match = re.search("XSpline\((.+)\)\n", current_line)
line_to_strip = match.group(1)
points = re.findall('(\(.*?\))', line_to_strip)
print(len(points))
for point in points:
print(point)
print("="*40)
file.close()
这给了我输出:
====init=====
Frames Per Second: 24.0
Source Width: 2048
Source Height: 778
Source Pixel Aspect Ratio: 1
Comp Pixel Aspect Ratio: 1
frame: 20
5
(0.793803,0.136326,0,0.5,0)
(0.772345,0.642332,0,0.5,0)
(0.6436,0.597615,0,0.5,0)
(0.70082,0.143387,0,0.5,0.25)
(0.70082,0.112791,0,0.5,0)
========================================
所以我需要的是能够分配(0.793803,0.136326,0,0.5,0)到(1x,1y,1z,1w,1s),(0.772345,0.642332,0,0.5,0)到(2x,2y,2z,2w,2s)等等,这样无论什么数字填补这些位置,他们都会接受这个价值。
这是我需要将这些数字放入的代码:
#-------------------------------------------------------------------------------
# Name: Mocha Rotoscoping Via Blender
# Purpose: Make rotoscoping more efficient
#
# Author: Jeff Owens
#
# Created: 11/07/2011
# Copyright: (c) jeff.owens 2011
# Licence: Grasshorse
#-------------------------------------------------------------------------------
#!/usr/bin/env python
import sys
import os
import parser
sys.path.append('Z:\_protomotion\Prog\HelperScripts')
import GetDir
sys.path.append('Z:\_tutorials\01\tut01_001\prod\Blender_Test')
filename = 'diving_board.shape4ae'
infile = 'Z:\_tutorials\01\tut01_001\prod\Blender_Test'
import bpy
from mathutils import Vector
#below are taken from mocha export
x_width =2048
y_height = 778
z_depth = 0
frame = 20
def readText():
text_file = open('diving_board.shape4ae', 'r')
lines = text_file.readlines()
print (lines)
print (len.lines)
for line in lines:
print (line)
##sets points final x,y,z value taken from mocha export for blender interface
point1x = (0.642706 * x_width)
point1y = (0.597615 * y_height)
point1z = (0 * z_depth)
point2x = (0.770557 * x_width)
point2y = (0.647039 * y_height)
point2z = (0 * z_depth)
point3x = (0.794697 * x_width)
point3y = (0.0869024 * y_height)
point3z = (0 * z_depth)
point4x = (0.707973* x_width)
point4y = (0.0751348 * y_height)
point4z = (0 * z_depth)
w = 1 # weight
listOfVectors = [Vector((point1x,point1y,point1z)),Vector((point2x,point2y,point2z)),Vector((point3x,point3 y,point3z)),Vector((point4x,point4y,point4z)), Vector((point1x,point1y,point1z))]
def MakePolyLine(objname, curvename, cList):
curvedata = bpy.data.curves.new(name=curvename, type='CURVE')
curvedata.dimensions = '3D'
objectdata = bpy.data.objects.new(objname, curvedata)
objectdata.location = (0,0,0) #object origin
bpy.context.scene.objects.link(objectdata)
polyline = curvedata.splines.new('POLY')
polyline.points.add(len(cList)-1)
for num in range(len(cList)):
x, y, z = cList[num]
polyline.points[num].co = (x, y, z, w)
MakePolyLine("NameOfMyCurveObject", "NameOfMyCurve", listOfVectors)
所以我有我的矢量,我希望能够放置(px,py,0.z,pw,ps)然后(p2.x,p2.y,p2.zp2.wp2.s)等等它可以根据给定的数字改变
任何帮助都会很棒..提前谢谢你!
-Jeff
答案 0 :(得分:3)
您可以创建点对象并按名称对其进行索引,而不是打印每个输出。例如:
>>> class Point:
... def __init__(self, t):
... (self.x,self.y,self.z,self.w,self.s) = t
...
>>> p = Point( (3,4,5,3,1) )
>>> p.w
3
您可以将这些点对象放在一个数组中,然后通过
访问组件myPoints[3].x
<强>附录强>
如果不从数组中提取点数,而不是使用实际变量名称,那么可以执行以下操作,{{1} }是你的元组数组:
points
等等。
请考虑这是否是一种合适的方法。拥有一个点类可以让你拥有任意数量的积分。使用已定义的变量名称,可以动态创建无限数量的这些内容,但几乎总是一个坏主意。以下是关于这样做的警告:http://mail.python.org/pipermail/tutor/2005-January/035232.html。
当你有一个点对象数组时,你可以做得更好!例如,您可以执行以下操作:
(p0x,p0y,p0z,p0w,p0s) = points[0]
(p1x,p1y,p1z,p1w,p1s) = points[1]
(p2x,p2y,p2z,p2w,p2s) = points[2]
...
从而改变第i个点的y坐标。修复变量名后,这几乎是不可能的。希望有所帮助! (希望我理解你的澄清!如果不是,请告诉我......)
答案 1 :(得分:0)
如果我正确地阅读你的代码,那么相关部分就是产生你的元组的循环。
data = []
for point in points:
data.append(point)
print(point)
这将创建一个新列表并将每个元组添加到列表中。因此,data[0]
持有(0.793803,0.136326,0,0.5,0)
,data[0][0]
持有0.793803
。