我有这个数组:
Array ( [0] =>
Array (
[0] => Array (
[07] => Array (
[2] => 352.9
[3] => 375737
[4] => 1000000002
) )
[1] => Array (
[07] => Array (
[2] => 362.1
[3] => 375797
[4] => 1000000002
) )
)
Array ( [1] =>
[0] => Array (
[08] => Array (
[2] => 305.7
[3] => 375857
[4] => 1000000002
) )
)
)
我需要一个关键07(月份)的最终数组总和,如下所示:
Array ( [0] =>
Array (
[0] => Array (
[07] => Array (
[2] => 3254.9 ( the sum of each 07 )
[3] => 6521545 ( the sum )
[4] => 98474916521621 ( the sum )
) )
)
Array ( [1] =>
[0] => Array (
[08] => Array (
[2] => 305.7 ( not summed cause month 08 is only one )
[3] => 375857 ""
[4] => 1000000002 ""
) )
)
)
任何帮助?
答案 0 :(得分:1)
在这里,尝试一下 - 我确信它既不是一个完美的解决方案也不是最佳解决方案(3个foreach-es),但它适用于相当大的数据集......
$ inputArray是包含您提供的数据的多维数组,顺便说一句......
编辑:修正版:
$result = array();
foreach( $inputArray as $subArray ) {
foreach ( $subArray as $subKey => $member ) {
if ( empty( $result[$subKey]) ) {
$result[$subKey] = $member;
} else {
foreach ( $member as $id => $subMember ) {
if ( empty( $result[$subKey][$id]) ) {
$result[$subKey][$id] = $subMember;
} else {
$result[$subKey][$id] += $subMember;
}
}
}
}
}
EDIT2:由于你改变了数组的格式,解决方案是不同的:
注意:$ array1和$ array2是您的“全局” - 预定义数组。
$arrayWrapper = array_merge( ( array ) $array1, ( array ) $array2 );
$result = array();
foreach ( $arrayWrapper as $inputArray ) {
foreach( $inputArray as $subArray ) {
foreach ( $subArray as $subKey => $member ) {
if ( empty( $result[$subKey]) ) {
$result[$subKey] = $member;
} else {
foreach ( $member as $id => $subMember ) {
if ( empty( $result[$subKey][$id]) ) {
$result[$subKey][$id] = $subMember;
} else {
$result[$subKey][$id] += $subMember;
}
}
}
}
}
}
使用您的数据进行测试,应该可以正常工作。
干杯。