模型
<?php
class Tonguetwister extends AppModel {
var $name = 'Tonguetwister';
//The Associations below have been created with all possible keys, those that are not needed can be removed
var $belongsTo = array(
'language' => array(
'className' => 'language',
'foreignKey' => 'language_alias',
'dependent'=> true
)
);
}
?>
控制器
<?php
class TonguetwistersController extends AppController {
var $name = 'Tonguetwisters';
var $uses = array('Tonguetwister', 'Language');
function index() {
$this->set('languages', $this->Language->find('all'));
}
function view($id = null) {
if (!$id) {
$this->Session->setFlash(__('Invalid tonguetwister', true));
$this->redirect(array('action' => 'index'));
}
$this->set('tonguetwisters', $this->Tonguetwister->find('all', array('conditions' => array('language_alias' => $id))));
}
}
?>
我只想在index()上看到有绕口令的语言。我怎么能这样做?
答案 0 :(得分:2)
可能有一种更有效的方法,但这里是如何从Tonguetwister表中选择唯一的语言:
function index() {
$languageList = $this->Tonguetwister->find(
'list',
array(
'fields' => array( 'language_alias', 'language_alias' ),
'group' => 'Tonguetwister.language_alias',
'recursive' => -1
)
);
// $languageList is now an array that holds the language ids
$this->set(
'languages',
$this->Tonguetwister->Language->find(
'all',
array(
'conditions' => array(
'Language.id' => $languageList
)
)
)
);
}
顺便说一下,您不需要将语言放入$uses
。由于它们具有关系集,因此您可以使用$this->Tonguetwister->Language
访问语言模型。
答案 1 :(得分:1)
你真的不需要为此做两个SQL查询。如果表格在“language_alias”上加入,您可以执行以下操作:
function index() {
$this->Language->recursive = 0;
$this->set('languages', $this->Language->find('all', array(
'conditions' => array($this->Language->alias.'.language_alias' => $this->Tonguetwister->alias.'.language_alias')
));
}
您应该只执行一个将正确连接表的查询。