在我的应用程序中,我有一个自定义AlertDialog(由系统使用showDialog()处理),其中包含一个带有2个选项卡的tabhost。其中一个标签是一个旋转器。只要微调器未打开(显示微调器对话框),我就可以毫无问题地旋转屏幕。如果旋转器在旋转过程中打开,我会得到:
FATAL EXCEPTION: main
java.lang.IllegalArgumentException: View not attached to window manager
at android.view.WindowManagerImpl.findViewLocked(WindowManagerImpl.java:355)
at android.view.WindowManagerImpl.removeView(WindowManagerImpl.java:200)
at android.view.Window$LocalWindowManager.removeView(Window.java:432)
at android.app.Dialog.dismissDialog(Dialog.java:278)
at android.app.Dialog.access$000(Dialog.java:71)
at android.app.Dialog$1.run(Dialog.java:111)
at android.app.Dialog.dismiss(Dialog.java:268)
at android.widget.Spinner.onDetachedFromWindow(Spinner.java:89)
at android.view.View.dispatchDetachedFromWindow(View.java:6173)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1164)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewGroup.dispatchDetachedFromWindow(ViewGroup.java:1162)
at android.view.ViewRoot.dispatchDetachedFromWindow(ViewRoot.java:1746)
at android.view.ViewRoot.doDie(ViewRoot.java:2757)
at android.view.ViewRoot.handleMessage(ViewRoot.java:1995)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:130)
at android.app.ActivityThread.main(ActivityThread.java:3683)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:507)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597)
at dalvik.system.NativeStart.main(Native Method)
因此...
1 - 是否可以在onPause()
期间以编程方式关闭微调器?
2 - 我应该使用不同的方法吗?
3 - 如果没有合适的解决方案,我该如何捕捉这个特殊的例外? (我知道不好的做法,但需要停止崩溃,并且由于活动在被销毁后正确地重建自己,无论如何都无关紧要。
...请为所有圣洁的爱而欢迎,不要建议我在活动声明中添加android:configChanges="orientation"
。令我感到惊讶的是,作为定向问题的官方解决方案,这种情况经常被接受。
修改其他信息
这是我的对话框创建代码供参考:
static final int ID_DIALOG_CHOOSER = 1;
int pref_location;
private Dialog dialog;
...
protected Dialog onCreateDialog(int id)
{
switch(id)
{
case ID_DIALOG_CHOOSER:
dialog = show(ID_DIALOG_CHOOSER);
break;
}
return dialog;
}
...
showDialog(DialogView.ID_DIALOG_CHOOSER);
...
Dialog show(final int dialogType)
{
if (dialogType == ID_DIALOG_CHOOSER)
{
AlertDialog.Builder builder = new AlertDialog.Builder(this);
// inflate tabhost layout
View tabHostLayout = (View) inflater.inflate(R.layout.tabhost_layout, null);
FrameLayout tabContent = (FrameLayout) tabHostLayout.findViewById(android.R.id.tabcontent);
// inflate tab content layouts and add to tabhost layout
LinearLayout tab1 = (LinearLayout) inflater.inflate(R.layout.dialog_tab1, null);
tabContent.addView(tab1);
LinearLayout tab2 = (LinearLayout) inflater.inflate(R.layout.dialog_tab2, null);
tabContent.addView(tab2);
// tab setup
TabHost tabHost = (TabHost) tabHostLayout.findViewById(R.id.TabHost_Dialog_Tabs);
tabHost.setup();
TabHost.TabSpec tab_1 = tabHost.newTabSpec("Category 1");
tab_1.setContent(R.id.LinearLayout_Dialog_Tab1_Content);
tab_1.setIndicator(this.getResources().getString(R.string.dialog_tab1), this.getResources().getDrawable(R.drawable.tabhost_icon_selector));
tabHost.addTab(tab_1);
TabHost.TabSpec tab_2 = tabHost.newTabSpec("Category 2");
tab_2.setContent(R.id.LinearLayout_Dialog_Tab2_Content);
tab_2.setIndicator(this.getResources().getString(R.string.dialog_tab2), this.getResources().getDrawable(R.drawable.tabhost_icon_selector));
tabHost.addTab(tab_2);
// spinner setup
final Spinner spinner_location = (Spinner) tab1.findViewById(R.id.Spinner_Dialog_Location);
String[] locationArrayVals = null;
ArrayAdapter<CharSequence> adapter_location = null;
locationArrayVals = this.getResources().getStringArray(R.array.location_array_vals);
adapter_location = ArrayAdapter.createFromResource(this, R.array.location_array_listdisplay, android.R.layout.simple_spinner_item);
adapter_location.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner_location.setAdapter(adapter_location);
// ok button
Button button_ok = (Button) tab1.findViewById(R.id.Button_Dialog_OK);
button_ok.setOnClickListener(new View.OnClickListener()
{
public void onClick(View view)
{
pref_location = spinner_location.getSelectedItemPosition();
dialog.dismiss();
}
});
// create dialog
builder.setTitle("Location")
.setView(tabHost)
.setCancelable(true);
dialog = builder.create();
}
return dialog;
}
使用临时解决方法进行编辑
对于任何感兴趣的人,我设法通过子类化微调器并覆盖onDetachedFromWindow()
来至少停止崩溃:
public static class CatchingSpinner extends Spinner
{
public CatchingSpinner(Context context, AttributeSet attrs)
{
super(context, attrs);
}
@Override
protected void onDetachedFromWindow()
{
try
{
super.onDetachedFromWindow();
}
catch (IllegalArgumentException e)
{
// do whatever
}
}
}
像我说的那样,一种解决方法。仍在努力解决方案。 :/
答案 0 :(得分:3)
我找到了更好的解决方案。用一个看起来和行为像Spinner的按钮替换Spinner实际上并不是那么困难(幸运的是崩溃除外)。
<Button
android:background="@android:drawable/btn_dropdown"
android:gravity="left|center_vertical"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
public void showSpinner() {
AlertDialog.Builder builder = new AlertDialog.Builder(getContext());
builder.setTitle(_spinnerPrompt);
builder.setSingleChoiceItems(_spinnerOptions, _spinnerSelection,
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int item) {
_spinnerSelection = item;
_pseudoSpinner.setText(_spinnerOptions[item]);
_restoreSpinnerOnRestart = false;
dialog.dismiss();
}
});
builder.setOnCancelListener(new DialogInterface.OnCancelListener() {
@Override
public void onCancel(DialogInterface dialog) {
_restoreSpinnerOnRestart = false;
}
});
AlertDialog alert = builder.create();
_restoreSpinnerOnRestart = true;
alert.show();
}
@Override
public Bundle onSaveInstanceState() {
Bundle state = super.onSaveInstanceState();
state.putBoolean(STATE_SPINNER_RESTORE, _restoreSpinnerOnRestart);
state.putInt(STATE_SPINNER_SELECTION, _spinnerSelection);
return state;
};
@Override
public void onRestoreInstanceState(Bundle savedInstanceState) {
super.onRestoreInstanceState(savedInstanceState);
_spinnerSelection = savedInstanceState.getInt(STATE_SPINNER_SELECTION, -1);
_restoreSpinnerOnRestart = savedInstanceState.getBoolean(STATE_SPINNER_RESTORE);
_pseudoSpinner.setText(_spinnerOptions[_spinnerSelection]);
if (_restoreSpinnerOnRestart) {
showSpinner();
}
};
答案 1 :(得分:1)
好的,我想我找到了你的问题:dialog.dismiss();
你做的确很奇怪 - 你正在通过活动创建对话,但是说不要忽视它 - 这是两种不同的方法,你不能混合。您应该选择一种方法:dialog.show和dialog.dismiss或activity.showDialog()和activity.dismissDialog()&lt; - 这是更好的,因为处理方向更改。
你应该做的只是从类变量中删除对话框,到处使用activity.showDialog。可能你的问题是在onClick中解雇对话框。只需使用YourActivityName.this.dismissDialog(DIALOG_NUMBER)即可使用。
阅读更多关于开发者网站对话框的信息 - 我也有这样的问题并花了很长时间来了解它是如何工作的,但毕竟 - 对话框并不那么复杂;)
答案 2 :(得分:1)
我遇到了类似的崩溃。我在显示对话框时禁用了方向更改。
@Override
public void onDismiss(DialogInterface dialog) {
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_UNSPECIFIED);
}
@Override
public void onShow(DialogInterface dialog) {
int loadedOrientation = getResources().getConfiguration().orientation;
int requestedOrientation = ActivityInfo.SCREEN_ORIENTATION_UNSPECIFIED;
if (loadedOrientation == Configuration.ORIENTATION_LANDSCAPE) {
requestedOrientation = ActivityInfo.SCREEN_ORIENTATION_LANDSCAPE;
} else if (loadedOrientation == Configuration.ORIENTATION_PORTRAIT) {
requestedOrientation = ActivityInfo.SCREEN_ORIENTATION_PORTRAIT;
}
setRequestedOrientation(requestedOrientation);
}
注意:我实际上发现lock screen orientation没有可靠的方法。