map<string, string> info;
info["name"] = "something";
info["id"] = "5665";
在C ++中初始化这样的地图有什么更好的方法?
编辑:我想在没有任何c ++库或额外代码的情况下这样做。像这样:
info["name", "id"] = {"something", "5665"};
答案 0 :(得分:5)
使用Boost.Assignment库,您可以执行以下操作:
map<string,int> m;
insert( m )( "Bar", 1 )( "Foo", 2 );
就我个人而言,我认为这会伤害可读性,而且你最好以正常的方式做这件事。
答案 1 :(得分:4)
查看C++0x initializer list
功能。好多了:))
答案 2 :(得分:3)
Boost.Assign可能是C ++ 03中最好的。
#include <boost/assign/list_of.hpp>
#include <map>
#include <string>
int main()
{
using namespace std;
map<string, string> info = boost::assign::map_list_of("name", "something")("id", "5665");
}
答案 3 :(得分:1)
您可以通过使用预定义语法(例如key(tab)value
)加载文本文件或资源文件中的值来完成此操作。
您的文字/资源看起来像这样:
name something
id 5665
你只需要在一个循环中逐行解析它。
如果您有正则表达式,可以使用简单的(.+)\s(.+)
,其中第1组与您的键匹配,第2组与您的值匹配。
答案 4 :(得分:1)
最好的方法是使用C ++ 0x初始化列表。但是如果你的编译器还没有实现这个功能,你可以使用类似下面的类
/**
* Class that creates an std::map using a chained list syntax. For example:
*
* @code
*
* std::map<int, int> SomeMap = MapInit<int, int>(1, 10)(2, 20)(3, 30);
*
* @endcode
*
* @tparam Key
* The key data type to be stored in the map.
* @tparam Type
* The element data type to be stored in the map.
* @tparam Traits
* The type that provides a function object that can compare two element values as sort keys to
* determine their relative order in the map. This argument is optional and the binary predicate
* less<Key> is the default value.
* @tparam Allocator
* The type that represents the stored allocator object that encapsulates details about the map's
* allocation and deallocation of memory. This argument is optional and the default value is
* allocator<pair <const Key, Type> >.
*/
template< class Key, class Type, class Traits = std::less<Key>,
class Allocator = std::allocator< std::pair <const Key, Type> > >
class MapInit
{
/** Local map instance used to construct the output map */
std::map<Key, Type, Traits, Allocator> myMap_;
/* Disallow default construction */
MapInit();
/* Disallow copy construction */
MapInit( const MapInit& );
/* Disallow assignment */
MapInit& operator=( const MapInit& );
public:
/** An alias for the type of this object */
typedef typename MapInit<Key, Type, Traits, Allocator> self_type;
/** An alias for the key-value pairs being stored in the map */
typedef typename std::map<Key, Type, Traits, Allocator>::value_type value_type;
/**
* Constructor that accepts a key and value to be inserted in the map
*
* @param[in] key
* The key value of the element that is to be inserted
* @param[in] value
* The element to be inserted
*/
MapInit( const Key& key, const Type& value )
{
myMap_[key] = value;
}
/**
* Constructor that accepts a key-value pair to be inserted into the map
*
* @param[in] kvpair
* The key-value pair to be inserted
*/
MapInit( const value_type& kvpair )
{
myMap_[kvpair.first] = kvpair.second;
}
/**
* Function call operator overload that accepts a key and value to be inserted in the map
*
* @param[in] key
* The key value of the element that is to be inserted
* @param[in] value
* The element to be inserted
*
* @return Reference to the operand after inserting the element into the std::map
*/
self_type& operator()( const Key& key, const Type& value )
{
myMap_[key] = value;
return *this;
}
/**
* Function call operator overload that accepts a key-value pair to be inserted in the map
*
* @param[in] kvpair
* The key-value pair to be inserted
*
* @return Reference to the operand after inserting the key-value pair into the std::map
*/
self_type& operator()( const value_type& kvpair )
{
myMap_[kvpair.first] = kvpair.second;
return *this;
}
/**
* Typecast operator to convert the operand to an std::map
*
* @return The std::map constrcuted by the operand
*/
operator std::map<Key, Type, Traits, Allocator>()
{
return myMap_;
}
};
答案 5 :(得分:1)
Boost assign是进行STL容器初始化的最佳方式之一:
std :: vector,set,map的一些好例子可以在这里找到:
http://www.boost.org/doc/libs/1_47_0/libs/assign/doc/index.html#examples
答案 6 :(得分:0)
请参阅我对此类似问题的回答here。
这在C ++ 0x中非常容易。