Question

我是 swift 的新手，我正在为新的 swift 结果而苦苦挣扎。所以我有这个功能：

enum LoginOption {
    case signInWithApple
    case emailAndPassword(email: String, password: String, completion: Result<Data, Error>)
}

// func 1:  wrapped with a ui tapped button event:
    private func emailAuthenticationTapped() {
login(with: .emailAndPassword(email: email, password: password, completion: {res in
                // to do 
            }))

// func 2: generic function that routes to the right signIn function based on signIn type:

func login(with loginOption: LoginOption) {
    switch loginOption {
        case let .emailAndPassword(email, password, completion):
               handleSignInWith(email: email, password: password, completion: (Result<Data, Error>) -> Void)

// func 3: main async func to handle signin
private func signIn(email: String, password: String, completion: @escaping (Result<Data, Error>) -> Void) {
...
}

我收到此错误：

无法将 '((Result) -> Void).Type' 类型的值转换为预期的参数类型 '(Result) -> Void'

Answer 1

你需要这样称呼它

 signInWith(email: email, password: password) { res in
    // to do 
 }

或

signIn(email: email, password: password,completion: { res in
   // to do     
})

Answer 2

你传递的是类型，但你必须传递一个实例。

解决方案很简单：传递枚举大小写的 completion 值

func login(with loginOption: LoginOption) {
    switch loginOption {
        case let .emailAndPassword(email, password, completion):
               handleSignInWith(email: email, password: password, completion: completion)

并替换

enum LoginOption {
    case signInWithApple
    case emailAndPassword(email: String, password: String, completion: Result<Data, Error>)
}

与

enum LoginOption {
    case signInWithApple
    case emailAndPassword(email: String, password: String, completion: (Result<Data, Error>) -> Void)
}

Swift 结果类型转换

2 个答案: