检查用户:
FutureBuilder(
future: _userFuture,
builder: (_,userData){
switch(userData.connectionState){
case ConnectionState.none:
case ConnectionState.waiting:
case ConnectionState.active:
case ConnectionState.done:
if(!newUser.containsKey('Email')){
newUser=Map<String,String>.from(userData.data);
}
return Column(children:<Widget> [
Text(
newUser['Email'],
),
Text(
newUser!['Password'],
),
]);
}
return Container();
},
);
答案 0 :(得分:0)
您的未格式化代码很难说,但看起来 userData.data
被视为 Object?
类型。如果实际上是地图,可以通过FutureBuilder<T>
泛型类型指定:
FutureBuilder<Map<String, String>>(
future: userFuture,
builder: (_, userData) {
// ... Your builder
},
);
答案 1 :(得分:0)
尝试将您的数据显式转换为 Map。
改变这个
newUser=Map<String,String>.from(userData.data)
到这里
Object data = userData.data;
newUser = data as Map