Question

我正在尝试使用Java Calendar类定义Jalali Calendar。当我设置这样的jalali日期时会出现问题：

Calendar jCal = Calendar.getInstance();

jCal.set(1390, 1, 31); //Current year in this calendar

实际上，Jalali日历中的第二个月有31天。现在，当我打电话来获得月和日时，我得到：

int day = jCal.get(Calendar.MONTH);
int month = jCal.get(Calendar.DAY_OF_MONTH);

给出： day = 3＆amp;月= 2

似乎根据公历重新调整日期。同样，我无法使用getImeInMillis()或setTimeInMillis()

Calendar testCal = Calendar.getInstance();
testCal.set(1380, 1, 28);
long millis = testCal.getTimeInMillis();

testCal.setTimeInMillis(millis + 3 * 24 * 3600 * 1000);

int day = jCal.get(Calendar.MONTH);
int month = jCal.get(Calendar.DAY_OF_MONTH);

再次结果是day = 3＆amp;月= 2

你可以帮我解决这个问题吗？

Answer 1

但是你说那是Jalali日历？ ofc Java认为你正在使用Gregorian。也许你需要使用类似的东西 this

或做自己的JalaliCalendar类

Answer 2

// 00:00:00 UTC (Gregorian) Julian day 0,
// 0 milliseconds since 1970-01-01
public static final long MILLIS_JULIAN_EPOCH = -210866803200000L;
 // Milliseconds of a day calculated by 24L(hours) * 60L(minutes) *
// 60L(seconds) * 1000L(mili);
public static final long MILLIS_OF_A_DAY = 86400000L;

/**
 * The JDN of 1 Farvardin 1; Equivalent to March 19, 622 A.D.
 */
public static final long PERSIAN_EPOCH = 1948321;

private int persianYear;
private int persianMonth;
private int persianDay;

public static long persianToJulian(long year, int month, int day) {
    return 365L * ((ceil(year - 474L, 2820D) + 474L) - 1L) + ((long) Math.floor((682L * (ceil(year - 474L, 2820D) + 474L) - 110L) / 2816D)) + (PERSIAN_EPOCH - 1L) + 1029983L
            * ((long) Math.floor((year - 474L) / 2820D)) + (month < 7 ? 31 * month : 30 * month + 6) + day;
}

public void setPersianDate(int persianYear, int persianMonth, int persianDay) {
    this.persianYear = persianYear;
    this.persianMonth = persianMonth;
    this.persianDay = persianDay;
    setTimeInMillis(convertToMilis(persianToJulian(this.persianYear > 0 ? this.persianYear : this.persianYear + 1, this.persianMonth - 1, this.persianDay)));
}
public static long julianToPersian(long julianDate) {
    long persianEpochInJulian = julianDate - persianToJulian(475L, 0, 1);
    long cyear = ceil(persianEpochInJulian, 1029983D);
    long ycycle = cyear != 1029982L ? ((long) Math.floor((2816D * (double) cyear + 1031337D) / 1028522D)) : 2820L;
    long year = 474L + 2820L * ((long) Math.floor(persianEpochInJulian / 1029983D)) + ycycle;
    long aux = (1L + julianDate) - persianToJulian(year, 0, 1);
    int month = (int) (aux > 186L ? Math.ceil((double) (aux - 6L) / 30D) - 1 : Math.ceil((double) aux / 31D) - 1);
    int day = (int) (julianDate - (persianToJulian(year, month, 1) - 1L));
    return (year << 16) | (month << 8) | day;
}
protected void calculatePersianDate() {
    long julianDate = ((long) Math.floor((getTimeInMillis() - MILLIS_JULIAN_EPOCH)) / MILLIS_OF_A_DAY);
    long PersianRowDate = julianToPersian(julianDate);
    long year = PersianRowDate >> 16;
    int month = (int) (PersianRowDate & 0xff00) >> 8;
    int day = (int) (PersianRowDate & 0xff);
    this.persianYear = (int) (year > 0 ? year : year - 1);
    this.persianMonth = month;
    this.persianDay = day;

}

Answer 3

month中的Calendar基于零。请参阅Calendar.MONTH。

编辑：也许{JALli日历的this实施可以帮助您。

Android日历课程月份的日期设置问题

3 个答案: