我正在尝试制作一个票务机器人,这就是我目前拥有的。现在我可以让机器人在检测到一个反应后创建一个通道,我需要能够让它关闭另一个反应的工单,以及我想要添加的其他功能。但是这种反应是在创建的频道中,所以我不知道如何创建该频道 ID。有人建议我使用齿轮,但不知道从哪里开始。
async def on_raw_reaction_add(payload):
channel = payload.channel_id
if channel == 862711339298455563:
guildid = payload.guild_id
guild = client.get_guild(guildid)
channel = guild.get_channel(payload.channel_id)
message = channel.get_partial_message(payload.message_id)
emoji = '?️'
member = payload.member
payloaduserid = payload.user_id
clientuserid = client.user.id
if payloaduserid != clientuserid:
await message.remove_reaction(emoji, member)
category = client.get_channel(861003967000215583)
channel1 = await guild.create_text_channel(f'ticket {payload.user_id}', category = category )
ticketembed = discord.Embed(
title = f'Ticket - {payload.user_id}',
description = '- If you want to tag the admins please react with :telephone: \n - To report this message please react with :warning: \n - To close the ticket react this mesaage with :x: ',
color = discord.Color.red())
ticketembed.set_footer(text = 'All of the conversation will be held in the archives, eventhought a moderator can delete a message in this channel, a copy of it will be held in a location where only the owner can access.')
user = client.get_user(payload.user_id)
await channel1.set_permissions(target=user, read_messages=True , send_messages=True)
ticketembed1 = await channel1.send(embed= ticketembed)
await ticketembed1.add_reaction('☎️')
await ticketembed1.add_reaction('⚠️')
await ticketembed1.add_reaction('❌')
await channel1.send(f'{user.mention}', delete_after = 0.1) ```
答案 0 :(得分:0)
一种方法是检查频道名称格式。有时无法从缓存中获取通道,因此我们可能需要获取它。
async def on_raw_reaction_add(payload):
channel = client.get_channel(payload.channel_id)
# if channel is not in cache then fetch is using a API request
if not channel:
channel = await client.fetch_channel(channel_id)
# The user is the owner of the ticket since it is his id
if channel.name == f"ticket {payload.user_id}":
emoji = payload.emoji.name
# delete
if emoji == "❌":
await channel.delete()
最好保存频道ID然后使用它,因为频道名称可以更改。可以这样获取id。
channel1 = await guild.create_text_channel(f'ticket {payload.user_id}', category = category )
print(channel1.id)