Question

这是来自 LEETCODE 的一个问题。我不知道为什么我的输出是错误的。首先，我在括号中写入 SELECT 以找出重复的电子邮件地址。然后我使用 DELETE 过滤掉重复的电子邮件地址，这样有人知道我的代码有什么问题吗？ question mycode output

Answer 1

很简单。试试这个

-- 解决方案 1

router.get("/", (req, res) => {
  console.log(Questions);

  // Questions.then(() => {
  //   res.send(Questions);
  // }) 

   res.status(200).send({
     res: "Success",



   }
    const newData = Questions;
  newData.forEach(function(obj, i) {
  obj['answer'] && delete obj['answer'];
});
  
  res.send(newData);
   
   );
 
  


});

-- 解决方案 2

with cte as
(
    select id, email, Rank() OVER (partition by email order by id) ranks
    from person where email in(
        select email from person
        group by email having count(email) >1
    )
)
DELETE FROM person where id in
(
    SELECT id FROM CTE where ranks!=1
)

Leetcode 上的 mysql 问题

1 个答案: