我希望在工作簿中列出所有选项卡名称,我遵循了用户 Iamblichus 的回复,并且效果很好。我唯一想排除工作簿中的 4 个特定选项卡。脚本如下:
function createOnChangeTrigger() {
const ss = SpreadsheetApp.getActive();
ScriptApp.newTrigger("writeSheetNames")
.forSpreadsheet(ss)
.onChange()
.create();
}
function writeSheetNames() {
const ss = SpreadsheetApp.getActive();
const sheetNames = ss.getSheets().map(sheet => [sheet.getName()]);
const sheet = ss.getSheetByName("Sheet24");
sheet.getRange("A:A").clear(); // Delete previous data
sheet.getRange(1,1,sheetNames.length).setValues(sheetNames);
}
首先创建一个触发器然后执行。想要排除 4 个特定选项卡。谢谢。
在此处找到原始帮助: List names of sheets in Google Sheets
答案 0 :(得分:1)
function writeSheetNames() {
const excl = ['Sheet1'];//sheet names to exclude
const ss = SpreadsheetApp.getActive();
const sheetNames = ss.getSheets().map(sheet => [sheet.getName()]).filter(n => !~excl.indexOf(n[0]));
const sheet = ss.getSheetByName("Sheet24");
sheet.getRange("A:A").clear(); // Delete previous data
sheet.getRange(1,1,sheetNames.length).setValues(sheetNames);
}