Question

我试图用 JSON 在 discord.py 上为我的关卡系统创建排行榜命令，但由于某种奇怪的原因，它不起作用。只显示前 3 名最高级别的球员，而不是前 5 名，当我尝试给另一个球员大量经验以改变第一名时，最后一名第一名的球员不会去第二名，但无处可寻.

这是输出图片，上面是我没有改变Void的exp时的输出，下面是我改变Void的exp时的输出。

    # leaderboard command
    @commands.command(name='leaderboard', aliases=['lb', 'top', 'levels'])
    async def leaderboard(self, ctx, arg:str=None):
        try:
            with open(levelsJSON, 'r') as levels_file:
                    levels = json.load(levels_file)

           ## Top 5 places VARIABLES
            first_name = 'N/A'
            first_level = 0
            first_exp = 0
            second_name = 'N/A'
            second_level = 0
            second_exp = 0
            third_name = 'N/A'
            third_level = 0
            third_exp = 0
            fourth_name = 'N/A'
            fourth_level = 0
            fourth_exp = 0
            fifth_name = 'N/A'
            fifth_level = 0
            fifth_exp = 0

           ## Variables END

            # loops through the file
            for user in levels:
                exp = float(levels[user]['exp'])
                level = float(levels[user]['level'])
                name = levels[user]['name']
                if exp > first_exp:
                    first_name = name
                    first_level = level
                    first_exp = exp
                elif exp > second_exp:
                    second_name = name
                    second_level = level
                    second_exp = exp
                elif exp > third_exp:
                    third_name = name
                    third_level = level
                    third_exp = exp
                elif exp > fourth_exp:
                    fourth_name = name
                    fourth_level = level
                    fourth_exp = exp
                elif exp > fifth_exp:
                    fifth_name = name
                    fifth_level = level
                    fifth_exp = exp
                else:
                    pass
            await ctx.send(f"1. {first_name}\n2. {second_name}\n3. {third_name}\n4. {fourth_name}\n5. {fifth_name}")
        except Exception as error:
            await ctx.send(f'```{error}```')

这是存储数据的 JSON 文件。

{
    "586579525849186315": {
        "name": "MythCraftMC#0963",
        "level": 8,
        "exp": 2174.21875,
        "max_exp": 2562.890625
    },
    "658633474995126282": {
        "name": "Regney#2226",
        "level": 3,
        "exp": 100.0,
        "max_exp": 337.5
    },
    "586579523549196315": {
        "name": "Void#0363",
        "level": 0,
        "exp": 32345,
        "max_exp": 100
    },
    "586579522449186315": {
        "name": "Universal_Kid#0963",
        "level": 4,
        "exp": 350,
        "max_exp": 500
    },
    "586572525844186315": {
        "name": "ThatOneGuy#0453",
        "level": 3,
        "exp": 300,
        "max_exp": 400
    }
}

[没有错误]

Answer 1

尝试采用不同的实现方式。首先，我们可以制作一个列表来跟踪用户。

userList = []
for user in levels
    exp = float(levels[user]['exp'])
    level = float(levels[user]['level'])
    name = levels[user]['name']
    userList.append([exp, level, name])
userList = sorted(userList, key=lambda x:x[1], reverse=True)

这将用所有用户填充 userList，并根据级别对它们进行排序。然后，我们可以打印该列表中的前 x 项。

await ctx.send(f"1. {userList[0][2]}\n2. {userList[1][2]}\n3. {userList[2][2]}\n4. {userList[3][2]}\n5. {userList[4][2]}")

有了这个，你可以去掉代码中的所有变量名和所有 if 语句，让它像你想要的那样动态。

排行榜命令 Discord.py 用 JSON 重写

1 个答案: