JComboBox无法在jTable中打开

时间:2011-07-25 18:12:28

标签: java swing jtable jcombobox tablecelleditor

我创建了一个表格,其中每行的单元格中都会显示一个组合框。我分别使用了以下两个类作为单元格编辑器和单元格渲染器。以某种方式显示表格时,单元格中的每个组合框在单击时都不会打开。任何人都可以给我一个提示吗?提前致谢

public class CellEditor extends DefaultCellEditor{

private static final long serialVersionUID = 1L;

public CellEditor(String[] items) {
    super(new JComboBox(items));
}
}

public class ComboBoxRenderer extends JComboBox implements TableCellRenderer {
/****/
private static final long serialVersionUID = 1L;

public ComboBoxRenderer(String[] items) {
    super(items);
}

public Component getTableCellRendererComponent(JTable table, Object value,
        boolean isSelected, boolean hasFocus, int row, int column) {

    if (isSelected) {
        this.setForeground(table.getSelectionForeground());
        super.setBackground(table.getSelectionBackground());
    } else {
        this.setForeground(table.getForeground());
        this.setBackground(table.getBackground());
    }        
    this.setSelectedItem(value);// Select the current value      
    return this;
}
}

1 个答案:

答案 0 :(得分:1)

请阅读JTable的教程,Editors and RenderersUsing a Combo Box as an Editor,此论坛上的一些示例(包含JTable中的AutoCompleted JComboBox)或here或{{ 3}}

但基本上是你的问题,(检查你是否设定了)

public boolean isCellEditable(int row, int col) {
    if (col == someInt) {
        return true;
    } else if (col == TableColumnsStartsWithZero) {
        return true;
    } else {
        return false;
    }
}