Question

我有一个程序，我们创建一个exe用于分发。我的客户运行XP和Vista和7.我们试图通过调整日志文件在Win7和Vista中写入的位置来简化安装，因为我们不必担心在XP中。我们尝试使用platform.release()来决定在何处编写日志文件。如果它不是XP，那么我们将日志文件写入os.environ["LOCALAPPDATA"]指定的位置。

我只是想确保在XP机器上运行时我们只能获得'XP'作为返回值，对于Vista和7我们也只会得到那些预期的结果。例如，有一些XP的风格将返回XP.v2（我做了吗？）

我们已经用Google搜索了答案，找不到任何具体到可以确定的内容。

感谢您的帮助。干杯

Answer 1

最终答案可以在源代码中找到Python解释器的确切版本。我正在使用CPython 2.7.1。它的源代码可以免费下载，这里是相关代码（在Lib/platform.py中找到）：

winver = GetVersionEx()
maj,min,buildno,plat,csd = winver
version = '%i.%i.%i' % (maj,min,buildno & 0xFFFF)
if hasattr(winver, "service_pack"):
    if winver.service_pack != "":
        csd = 'SP%s' % winver.service_pack_major
else:
    if csd[:13] == 'Service Pack ':
        csd = 'SP' + csd[13:]

if plat == VER_PLATFORM_WIN32_WINDOWS:
    regkey = 'SOFTWARE\\Microsoft\\Windows\\CurrentVersion'
    # Try to guess the release name
    if maj == 4:
        if min == 0:
            release = '95'
        elif min == 10:
            release = '98'
        elif min == 90:
            release = 'Me'
        else:
            release = 'postMe'
    elif maj == 5:
        release = '2000'

elif plat == VER_PLATFORM_WIN32_NT:
    regkey = 'SOFTWARE\\Microsoft\\Windows NT\\CurrentVersion'
    if maj <= 4:
        release = 'NT'
    elif maj == 5:
        if min == 0:
            release = '2000'
        elif min == 1:
            release = 'XP'
        elif min == 2:
            release = '2003Server'
        else:
            release = 'post2003'
    elif maj == 6:
        if hasattr(winver, "product_type"):
            product_type = winver.product_type
        else:
            product_type = VER_NT_WORKSTATION
            # Without an OSVERSIONINFOEX capable sys.getwindowsversion(),
            # or help from the registry, we cannot properly identify
            # non-workstation versions.
            try:
                key = RegOpenKeyEx(HKEY_LOCAL_MACHINE, regkey)
                name, type = RegQueryValueEx(key, "ProductName")
                # Discard any type that isn't REG_SZ
                if type == REG_SZ and name.find("Server") != -1:
                    product_type = VER_NT_SERVER
            except WindowsError:
                # Use default of VER_NT_WORKSTATION
                pass

        if min == 0:
            if product_type == VER_NT_WORKSTATION:
                release = 'Vista'
            else:
                release = '2008Server'
        elif min == 1:
            if product_type == VER_NT_WORKSTATION:
                release = '7'
            else:
                release = '2008ServerR2'
        else:
            release = 'post2008Server'

else:
    if not release:
        # E.g. Win3.1 with win32s
        release = '%i.%i' % (maj,min)
    return release,version,csd,ptype

在阅读此代码后，我不希望在Windows XP盒子上看到{XP}以外的release值。

我怎样才能确定platform.release（）的可能返回值

1 个答案: