Question

我有3个可以通过id加入的XML文件。

 var test = from b in doc.Descendants("CalendarFair")
                        let start = b.Element("DateStart").Value
                        where 
                          start.Substring(0, 2) == dateNow.Substring(0, 2) &&
                          start.Substring(6, 4) == dateNow.Substring(6, 4)
                        let id1 = b.Element("IdExecutive").Value
                        join c in doc1.Descendants("Executive")
                        on id1 equals c.Element("Id").Value

                        select new
                        {
                            Title = b.Element("Title").Value,
                            DateStart=b.Element("DateStart").Value,
                            DateEnd=b.Element("DateEnd").Value, 
                            NameExecutive = c.Element("NameExecutive").Value,

                        };

此代码加入CalendarFair和Executive现在如何将FairCenter加入此代码

 var test = from b in doc.Descendants("CalendarFair")
                        let start = b.Element("DateStart").Value
                        where start.Substring(0, 2) == dateNow.Substring(0, 2) &&
                            start.Substring(6, 4) == dateNow.Substring(6, 4)
                        let id1 = b.Element("IdExecutive").Value
                        join c in doc1.Descendants("Executive")
                        on id1 equals c.Element("Id").Value
                        join d in doc3.Descendants("FairCenter")
                        on ........ //by id
                        select new
                        {
                            Title = b.Element("Title").Value,
                            DateStart=b.Element("DateStart").Value,
                            DateEnd=b.Element("DateEnd").Value, 
                            NameExecutive = c.Element("NameExecutive").Value,
                            telExecutive = c.Element("Tel").Value,
                            websiteExecutive = c.Element("Website").Value

                        };

FairCenter.xml

<FairCenters>
   <FairCenter>
      <Name>c1</Name>
      <Id>1</Id>
   </FairCenter>
  <FairCenter>
      <Name>c2</Name>
      <Id>1</Id>
   </FairCenter>

Executives.xml

<Executives>
   <Executive>
      <NameExecutive>e1</NameExecutive>
      <Id>1</Id>
  </Executive>
   <Executive>
      <NameExecutive>e2</NameExecutive>
      <Id>2</Id>
  </Executive>
</Executives>

CalendarFair.xml

<CalendarFairs>
  <CalendarFair>
     <DateStart>09/09/2011</DateStart>
     <DateEnd>07/15/2011</DateEnd>
     <Title>f1</Title>
     <IdExecutive>1</IdExecutive>
     <IdCenter>1</IdCenter>
  </CalendarFair>
  <CalendarFair>
      <DateStart>07/14/2011</DateStart>
      <DateEnd>07/20/2011</DateEnd>
      <Title>f2</Title>
      <IdExecutive>5</IdExecutive>
      <IdCenter>2</IdCenter>
  </CalendarFair>
</CalendarFairs>

答案

 var test = from b in doc.Descendants("CalendarFair")
                        let start = b.Element("DateStart").Value
                        where start.Substring(0, 2) == dateNow.Substring(0, 2) && start.Substring(6, 4) == dateNow.Substring(6, 4)
                        let id1 = b.Element("IdExecutive").Value
                        let id2 = b.Element("IdCenter").Value 
                        join c in doc1.Descendants("Executive")
                        on id1 equals c.Element("Id").Value
                        join d in doc3.Descendants("FairCenter")
                        on id2 equals d.Element("Id").Value
                        select new
                        {
                            Title = b.Element("Title").Value ,
                            DateStart=b.Element("DateStart").Value,
                            DateEnd=b.Element("DateEnd").Value, 
                              NameExecutive = c.Element("NameExecutive").Value,
                            telExecutive = c.Element("Tel").Value,
                            websiteExecutive = c.Element("Website").Value,
                            NameCenter = d.Element("Name").Value
                        };

Answer 1

在我看来，你只需要：

 join d in doc3.Descendants("FairCenter")
 on b.Element("IdFair").Value equals d.Element("Id").Value

是什么给你带来了麻烦？请注意，对于连接，您并不需要所有这些let语句。我认为会更清楚：

var test = from b in doc.Descendants("CalendarFair")
           where ...
           join c in doc1.Descendants("Executive")
             on b.Element("IdExecutive").Value equals c.Element("Id").Value
           join d in doc3.Descendants("FairCenter")
             on b.Element("IdFair").Value equals d.Element("Id").Value

这清楚地表明你在每个阶段都匹配哪些元素。

我假设您也想在投影中使用d ......

（顺便说一句，你应该看看将DateStart转换为DateTime，而不是使用所有这些子字符串操作。）

如何加入xml

1 个答案: