Question

这段python代码有问题吗？

我的问题是，当 run_again() 执行并在我键入“n”时要求输入时，一切正常，但是当我键入“y”时，run() 函数不执行。 为什么会这样？

我尝试在不创建函数的情况下执行 run_again() 过程，但它显示了相同的错误。

import random

print("Welcome to the Snake water gun game!")
chance = 1
counter = 10
player_p = 0
comp_p = 0
choices = ["Snake", "Water", "Gun"]

def run():
global choices
global chance
global player_p
global comp_p
global counter
while chance > 0 and chance <= 10:
    a = random.choice(choices)
    counter -= 1
    print("Choose one from below:\n1.Snake(s)\n2.Water(w)\n3.Gun(g)")
    decision = input("Type here:")
    if decision == "s" and a == "Snake":
        chance += 1
        print(f"Draw. {counter} times left.")
    elif decision == 's' and a == "Water":
        chance += 1
        print(f"You Won! {counter} times left.\n-------------------------------")
        player_p += 1
    elif decision == "s" and a == "Gun":
        chance += 1
        print(f"You lost. {counter} times left.\n-------------------------------")
        comp_p += 1
    elif decision == "w" and a == 'Snake':
        chance += 1
        print(f"You lost. {counter} times left.\n-------------------------------")
        comp_p += 1
    elif decision == "w" and a == "Water":
        chance += 1
        print(f"Draw. {counter} times left.\n-------------------------------")
    elif decision == "w" and a == "Gun":
        chance += 1
        print(f"You Won! {counter} times left.\n-------------------------------")
        player_p += 1
    elif decision == "g" and a == "Snake":
        chance += 1
        print(f"You Won! {counter} times left.\n-------------------------------")
        player_p += 1
    elif decision == "g" and a == "Water":
        chance += 1
        print(f"You lost. {counter} times left.\n-------------------------------")
        comp_p += 1
    elif decision == "g" and a == "Gun":
        chance += 1
        print(f"Draw. {counter} times left.\n-------------------------------")
    
run()

print("Your score:", player_p)
print("Computer's score:", comp_p)

def winner():
    if player_p > comp_p:
        print("------------------------\nYou Won! Congratulations")
    elif player_p < comp_p:
        print("------------------------\nComputer Won! Better luck next time.")
    else:
        print("---------------\nIt's a DRAW!")

winner()

def run_again():
    q = input("Do you want to play again(y/n):")
    if q == 'n':
        print("Oh, okay")
    elif q == 'y':
        run()
run_again()

Answer 1

您的代码有效

def run_again():
    q = input("Do you want to play again(y/n):")
    if q == 'n':
        print("Oh, okay")
    elif q == 'y':
        run()

def run():
  print("Hi")
run_again()

Answer 2

在给定的代码中没有你创建的run()函数，那怎么调用呢？您必须根据给定的代码创建一个名为 run() 的函数。请参阅以下代码以更好地理解：-

def run():
    print("Let's play again")
def run_again():
    q = input("Do you want to play again(y/n):")
    if q == 'n':
        print("Oh, okay")
    elif q == 'y':
        run()
run_again()

您可以根据自己的选择在更新后的代码中编辑 run() 函数。

如何在函数内部执行函数

2 个答案: