我想在两个时间戳之间创建一个日期范围。我看到了类似的帖子,还检查了 this 方法。但是,仍然无法达到下面的预期输出。
请注意,如果 ended_at
为 NULL,则需要取 CURRENT_TIMESTAMP
。
示例数据:
WITH t1 AS (
SELECT 'A' AS id, '2021-05-18 18:30:00'::timestamp AS started_at, '2021-05-19 09:45:00'::timestamp AS ended_at UNION ALL
SELECT 'B' AS id, '2021-05-24 11:30:40'::timestamp AS started_at, NULL::timestamp AS ended_at
)
SELECT *
FROM t1
预期结果:
答案 0 :(得分:2)
生成长度为 datedfiff 的空格数组,拆分数组并展平以生成行。使用索引作为添加到开始日期的天数:
WITH t1 AS (
SELECT 'A' AS id, '2021-05-18 18:30:00'::timestamp AS started_at, '2021-05-19 09:45:00'::timestamp AS ended_at UNION ALL
SELECT 'B' AS id, '2021-05-24 11:30:40'::timestamp AS started_at, NULL::timestamp AS ended_at
)
SELECT t1.*, dateadd(day, v.index, to_date(t1.started_at)) as date_generated
FROM t1,
lateral flatten (split(space(datediff(day,to_date(t1.started_at), nvl(to_date(t1.ended_at), current_date))),' ')) v
;
结果:
ID STARTED_AT ENDED_AT DATE_GENERATED
A 2021-05-18 18:30:00.000 2021-05-19 09:45:00.000 2021-05-18
A 2021-05-18 18:30:00.000 2021-05-19 09:45:00.000 2021-05-19
B 2021-05-24 11:30:40.000 null 2021-05-24
B 2021-05-24 11:30:40.000 null 2021-05-25
答案 1 :(得分:1)
如果您需要生成的天数相对较少,则可以使用递归 CTE:
WITH t1 AS (
SELECT
'A' AS id,
'2021-05-18 18:30:00'::timestamp AS started_at,
'2021-05-19 09:45:00'::timestamp AS ended_at
UNION ALL
SELECT
'B' AS id,
'2021-05-24 11:30:40'::timestamp AS started_at,
NULL::timestamp AS ended_at
),
row_gen (id, started, ended, generated_day) as (
select
t1.id id,
t1.started_at::date started,
coalesce(t1.ended_at, current_timestamp)::date ended,
started generated_day
from t1
union all
select
id,
started,
ended,
dateadd('day', 1, generated_day)
from row_gen
where generated_day < ended
)
SELECT *
FROM row_gen
+--+----------+----------+-------------+
|ID|STARTED |ENDED |GENERATED_DAY|
+--+----------+----------+-------------+
|A |2021-05-18|2021-05-19|2021-05-18 |
|A |2021-05-18|2021-05-19|2021-05-19 |
|B |2021-05-24|2021-05-25|2021-05-24 |
|B |2021-05-24|2021-05-25|2021-05-25 |
+--+----------+----------+-------------+