所以我想发送一个排行榜命令,但在一个嵌入中,但我似乎无法找到方法。这就是我能想到的|
const leaderboardEmbed = new Discord.MessageEmbed()
.setTitle('Leaderboard')
.setDescription('Top 10 leveled users are', message.channel.send(`**Leaderboard**:\n\n${lb.join("\n\n")}`))
message.channel.send(leaderboardEmbed);
答案 0 :(得分:0)
你可以试试:
class Node:
def __init__(self, key):
self.left = None
self.right = None
self.val = key
def printPreorder(root):
if root:
print(root.val),
printPreorder(root.left)
printPreorder(root.right)
class stack:
def __init__(self):
self.items = []
def push(self, item):
return self.items.append(item)
def pop(self):
return self.items.pop()
def size(self):
return len(self.items)
print ("Create 3 words using the letters")
root = Node('a')
root.right = Node('n')
root.left = Node ('t')
printPreorder(root)
print("-----------------------------------")
s1 = stack()
while (s1.size() <3):
try:
FirstList = (input("Enter the word you created: "))
if (FirstList == 'an'):
s1.push(FirstList)
elif (FirstList == 'ant'):
s1.push(FirstList)
elif (FirstList == 'tan'):
s1.push(FirstList)
finally:
print(s1.items)
legend1 = (input("Choose next move 1 = Countinue to the next round 2 = Show score3 = Exit Legend: "))
if legend1 == '3':
exit1 = (input("Are you sure you want to exit? 1 = yes 2 = no"))
if (exit1 == '1'):
break
elif (exit1 == '2'):
return
else:
print("Enter valid legend: ")
elif legend1 == '2':
print(s1.size())
elif legend1 == '1':
s2 = stack()
print ("Create 3 words using the letters")
root = Node('i')
root.right = Node('d')
root.left = Node ('m')
printPreorder(root)
print("-----------------------------------")
s1 = stack()
while (s2.size() <3):
try:
SecondList = (input("Enter the word you created: "))
if (SecondList == 'hid'):
s2.push(SecondList)
elif (SecondList == 'dim'):
s2.push(SecondList)
elif (SecondList == 'id'):
s2.push(SecondList)
finally:
print(s2.items)