我正在尝试将对象(键值)数组减少到一个对象(键值)。 我正在使用javascript中的json对象
我有这个:
"relations":
[
{"609e598ad32e90519043f09f": "609d8b78cf7bb100045fc593"},
{"609e5945d32e90519043f09e": "609d8b78cf7bb100045fc593"},
{"609e58b496d43235884e788f": "609d8b78cf7bb100045fc593"},
{"609e57e3e1560e58245544f4": "609d8de9575b49000466e358"}
],
以下是我的预期结果:
"relations":
{
"609e598ad32e90519043f09f":"609d8b78cf7bb100045fc593",
"609e5945d32e90519043f09e":"609d8b78cf7bb100045fc593",
"609e58b496d43235884e788f":"609d8b78cf7bb100045fc593",
"609e57e3e1560e58245544f4":"609d8de9575b49000466e358"
}
我怎样才能达到这个结果?
答案 0 :(得分:0)
您可以使用 for..in 循环获取 key-value
并使用 reduce 将其存储到对象中。然后您可以将其分配给 relations
属性。
let obj = {
relations: [
{ "609e598ad32e90519043f09f": "609d8b78cf7bb100045fc593" },
{ "609e5945d32e90519043f09e": "609d8b78cf7bb100045fc593" },
{ "609e58b496d43235884e788f": "609d8b78cf7bb100045fc593" },
{ "609e57e3e1560e58245544f4": "609d8de9575b49000466e358" },
],
};
const result = obj.relations.reduce((acc, curr) => {
for (let key in curr) {
acc[key] = curr[key];
}
return acc;
}, {});
obj.relations = result;
console.log(obj);
您也可以克隆对象并使用对象解构仅更改 relations
键
let obj = {
name: "test",
relations: [
{ "609e598ad32e90519043f09f": "609d8b78cf7bb100045fc593" },
{ "609e5945d32e90519043f09e": "609d8b78cf7bb100045fc593" },
{ "609e58b496d43235884e788f": "609d8b78cf7bb100045fc593" },
{ "609e57e3e1560e58245544f4": "609d8de9575b49000466e358" },
],
};
const result = obj.relations.reduce((acc, curr) => {
for (let key in curr) {
acc[key] = curr[key];
}
return acc;
}, {});
const cloneWithChanges = { ...obj, relations: result };
console.log(cloneWithChanges);