Question

我正在为WP7编码。我希望下面的代码能够阅读下面的XML：

_xml = XElement.Parse(e.Result);
                results.Items.Clear();
                foreach (XElement value in _xml
                    .Descendants("ResourceSets").Descendants("ResourceSet")
                    .Descendants("Resources").Descendants("Location"))
                {
                    Results _item = new Results();
                    _item.Place = value.Element("Name").Value;
                    _item.Lat = value.Element("Point").Element("Latitude").Value;
                    _item.Long = value.Element("Point").Element("Longitude").Value;

                    results.Items.Add(_item);
                }

但是foreach循环不会读取它并将其放在_items中。

<?xml version="1.0" encoding="utf-8" ?> 
 <Response xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://schemas.microsoft.com/search/local/ws/rest/v1">
  <Copyright>Copyright © 2011 Microsoft and its suppliers. All rights reserved. This API cannot be accessed and the content and any results may not be used, reproduced or transmitted in any manner without express written permission from Microsoft Corporation.</Copyright> 
  <BrandLogoUri>http://dev.virtualearth.net/Branding/logo_powered_by.png</BrandLogoUri> 
  <StatusCode>200</StatusCode> 
  <StatusDescription>OK</StatusDescription> 
  <AuthenticationResultCode>ValidCredentials</AuthenticationResultCode> 
  <TraceId>703e7f1427dd425185ded546ba8a0d2c|LTSM001154|02.00.126.3000|LTSMSNVM002008, LTSMSNVM001854, LTSMSNVM001853</TraceId> 
 <ResourceSets>
 <ResourceSet>
  <EstimatedTotal>4</EstimatedTotal> 
 <Resources>
 <Location>
  <Name>Ashford, Kent, United Kingdom</Name> 
 <Point>
  <Latitude>51.146636679768562</Latitude> 
  <Longitude>0.87603025138378143</Longitude> 
  </Point>
 <BoundingBox>
  <SouthLatitude>51.076602190732956</SouthLatitude> 
  <WestLongitude>0.72853825986385345</WestLongitude> 
  <NorthLatitude>51.21656522154808</NorthLatitude> 
  <EastLongitude>1.0235222429037094</EastLongitude> 
  </BoundingBox>
  <EntityType>PopulatedPlace</EntityType> 
 <Address>
  <AdminDistrict>England</AdminDistrict> 
  <AdminDistrict2>Kent</AdminDistrict2> 
  <CountryRegion>United Kingdom</CountryRegion> 
  <FormattedAddress>Ashford, Kent, United Kingdom</FormattedAddress> 
  <Locality>Ashford</Locality> 
  </Address>
  <Confidence>High</Confidence> 
  </Location>
  </Resources>
  </ResourceSet>
  </ResourceSets>
  </Response>

Answer 1

看起来你错过了每个元素名称的命名空间。试试这个：

XNamespace xns = "http://schemas.microsoft.com/search/local/ws/rest/v1";
_xml = XElement.Parse(e.Result);
results.Items.Clear();
foreach (XElement value in _xml
    .Descendants(xns + "ResourceSets").Descendants(xns + "ResourceSet")
    .Descendants(xns + "Resources").Descendants(xns + "Location"))
{
    Results _item = new Results();
    _item.Place = value.Element(xns + "Name").Value;
    _item.Lat = value.Element(xns + "Point").Element(xns + "Latitude").Value;
    _item.Long = value.Element(xns + "Point").Element(xns + "Longitude").Value;
    results.Items.Add(_item);
}

Answer 2

您使用后代有特殊原因吗？

你可以这样做：

XmlDocument doc = new XmlDocument();
doc.Load(YourXMLPath);
XmlNode locationNode = doc["ResourceSets"]["ResourceSet"]["Resources"]["Location"];
foreach(XmlElement value in locationNode.Children)
{
    Results _item = new Results();
                    _item.Place = value.Element("Name").Value;
                    _item.Lat = value.Element("Point").Element("Latitude").Value;
                    _item.Long = value.Element("Point").Element("Longitude").Value;

                    results.Items.Add(_item);

}

我现在没有VS，但那应该接近它。当然，一个好的行为是在获取下一个节点之前检查节点是否为空。

Answer 3

public ObservableCollection<Results> result = new ObservableCollection<Results>();

XDocument xmldoc = XDocument.Parse(e.Result.ToString());

var data = from c in xmldoc.Descendants("ResourceSets").Descendants("ResourceSet").Descendants("Resources").Descendants("Location")
    select new Results{
    Place = c.Element("Name").Value;
    Lat = c.Element("Point").Element("Latitude").Value;
    Long = c.Element("Point").Element("Longitude").Value;
    };
    foreach (Results obj in data) 
    {
        result.Add(obj);
    }

没试过，但这就是我的做法。

c＃来自后代的XML

3 个答案: