Question

我有一个主视图，其中包含一个landscapeview和一个portraitview，它被加载为包装器视图的子视图。横向视图和纵向视图都具有链接到它们的UIPickerView对象。在我的源代码中，我将它们全部作为属性，我还有一个景观和肖像选择器的包装器。它们被定义为

@property (nonatomic, retain, readonly) IBOutlet UIPickerView *pickerTown;
@property (nonatomic, retain, readonly) IBOutlet UIPickerView *pickerType;
@property (nonatomic, retain, readonly) IBOutlet UIDatePicker *pickerFrom;
@property (nonatomic, retain, readonly) IBOutlet UIDatePicker *pickerTo;

@property (nonatomic, retain) IBOutlet UIPickerView *landscapePickerTown;
@property (nonatomic, retain) IBOutlet UIPickerView *landscapePickerType;
@property (nonatomic, retain) IBOutlet UIDatePicker *landscapePickerFrom;
@property (nonatomic, retain) IBOutlet UIDatePicker *landscapePickerTo;

@property (nonatomic, retain) IBOutlet UIPickerView *portraitPickerTown;
@property (nonatomic, retain) IBOutlet UIPickerView *portraitPickerType;
@property (nonatomic, retain) IBOutlet UIDatePicker *portraitPickerFrom;
@property (nonatomic, retain) IBOutlet UIDatePicker *portraitPickerTo;

对于每个我只读的包装

- (UIPickerView *) pickerTown
{
    if(self.landscapeView.superview)
    {
        return landscapePickerTown;
    }else
    {
        return portraitPickerTown;
    }
}

但是当我在肖像或风景中时，我试图说出

myHelper.selectedTown = [myHelper.towns objectAtIndex:[pickerTown selectedRowInComponent:0]];

我没有得到选定的值，只是数组中的第一个值。

数据添加如下：

if(pickerView == landscapePickerType || pickerView == portraitPickerType) {
    return [myHelper.types objectAtIndex:row];
}else if(pickerView == landscapePickerTown || pickerView == portraitPickerTown){
    return [myHelper.towns objectAtIndex:row]; 
}else
{
    return @"";
}

和数组：

myHelper = [Helper sharedManager];
[myHelper.types addObject:@"None"];
[myHelper.types addObject:@"Food & Wine"];
[myHelper.types addObject:@"Test"];
[myHelper.towns addObject:@"None"];
[myHelper.towns addObject:@"Vanderbijlpark"];
[myHelper.towns addObject:@"Test"];

我在这里做错了什么？

Answer 1

如果您只获得第一个元素，则表示[pickerTown selectedRowInComponent:0]正在评估为零，但只有当pickerTown为nil时才会发生这种情况。这也很可能是由于插座没有连接。

但在这种情况下，我认为您是直接访问实例变量而不是方法返回的值。如果您对@synthesize使用pickerTown，请将其设为@dynamic。并将语句更改为[self.pickerTown selectedRowInComponent:0]以访问getter的值。

UIPickerView没有返回正确的数据

1 个答案: