在 AWS Lambda 测试中无法识别 lambda_function.py

时间:2021-04-21 11:43:54

标签: python amazon-web-services aws-lambda

我正在此 AWS 文档的第 4 步中了解如何使用 lambda 拆分 csv 数据 https://docs.aws.amazon.com/pinpoint/latest/developerguide/tutorials-importing-data-lambda-function-input-split.html

我已经按照建议创建了 lambda_function.py 文件并存储在根目录中

import os
import boto3
import s3fs
from botocore.exceptions import ClientError

input_archive_folder = "input_archive"
to_process_folder = "to_process"
file_row_limit = 50
file_delimiter = ','

# S3 bucket info
s3 = s3fs.S3FileSystem(anon=False)
    
def lambda_handler(event, context):
    print("Received event: \n" + str(event))
    for record in event['Records']:
        # Assign some variables that make it easier to work with the data in the 
        # event record.
        bucket = record['s3']['bucket']['name']
        key = record['s3']['object']['key']
        input_file = os.path.join(bucket,key)
        archive_path = os.path.join(bucket,input_archive_folder,os.path.basename(key))
        folder =  os.path.split(key)[0]
        s3_url = os.path.join(bucket,folder)
        output_file_template = os.path.splitext(os.path.basename(key))[0] + "__part"
        output_path = os.path.join(bucket,to_process_folder)
        
        # Set a variable that contains the number of files that this Lambda 
        # function creates after it runs.
        num_files = file_count(s3.open(input_file, 'r'), file_delimiter, file_row_limit)
        
        # Split the input file into several files, each with 50 rows.
        split(s3.open(input_file, 'r'), file_delimiter, file_row_limit, output_file_template, output_path, True, num_files)
        
        # Send the unchanged input file to an archive folder.
        archive(input_file,archive_path)
    
# Determine the number of files that this Lambda function will create.
def file_count(file_handler, delimiter, row_limit):
    import csv 
    reader = csv.reader(file_handler, delimiter=delimiter)
    # Figure out the number of files this function will generate.
    row_count = sum(1 for row in reader) - 1
    # If there's a remainder, always round up.
    file_count = int(row_count // row_limit) + (row_count % row_limit > 0)
    return file_count

# Split the input into several smaller files.
def split(filehandler, delimiter, row_limit, output_name_template, output_path, keep_headers, num_files):
    import csv 
    reader = csv.reader(filehandler, delimiter=delimiter)
    
    current_piece = 1
    current_out_path = os.path.join(
         output_path,
         output_name_template + str(current_piece) + "__of" + str(num_files) + ".csv"
    )
    current_out_writer = csv.writer(s3.open(current_out_path, 'w'), delimiter=delimiter)
    current_limit = row_limit
    if keep_headers:
        headers = next(reader)
        current_out_writer.writerow(headers)
    for i, row in enumerate(reader):
        if i + 1 > current_limit:
            current_piece += 1
            current_limit = row_limit * current_piece
            current_out_path = os.path.join(
               output_path,
               output_name_template + str(current_piece) + "__of" + str(num_files) + ".csv"
            )
            current_out_writer = csv.writer(s3.open(current_out_path, 'w'), delimiter=delimiter)
            if keep_headers:
                current_out_writer.writerow(headers)
        current_out_writer.writerow(row)

# Move the original input file into an archive folder.
def archive(input_file, archive_path):
    s3.copy_basic(input_file,archive_path)
    print("Moved " + input_file + " to " + archive_path)
    s3.rm(input_file)

我现在正在尝试使用 testfile.csv 在步骤 4.2 中运行测试事件 但是,当我运行测试时,它返回以下错误:

Response
{
  "errorMessage": "Unable to import module 'lambda_function': No module named 'lambda_function'",
  "errorType": "Runtime.ImportModuleError",
  "stackTrace": []
}

我从一开始就遵循文档中的每一步,确保将 lambda_function.py 文件保存到函数的根目录,甚至从头开始再试一次,但没有成功。谁能帮我指明正确的方向?

0 个答案:

没有答案