Question

我试图提示用户输入整数或字符串。 int 效果很好，但是每当我尝试输入字符串时，它都会给我错误“ValueError：int() 的无效文字，基数为 10：'green'”。我试过寻找答案，但没有运气。任何帮助将不胜感激。谢谢。

One =  "1 = Red"
Two = "2 = Blue"
Three = "3 = Yellow"
Four = "4 = Pink"
Five = "5 = Purple"

#Prints listed colors
print ("*List of Colors below*")
print (One + "\n" + Two + "\n" + Three + "\n" + Four + "\n" + Five)


num1 = str(input('What is your favorite color? You can either choose the number from the list above or enter your own color: '))

if (int(num1) == 1):
    print ('You chose the the first color from the list, which is: Red')
elif (int(num1) == 2):
    print ('You chose the the first color from the list, which is: Blue')
elif (int(num1) == 3):
    print ('You chose the the first color from the list, which is: Yellow')
elif (int(num1) == 4):
    print ('You chose the the first color from the list, which is: Pink')
elif (int(num1) == 5):
    print ('You chose the the first color from the list, which is: Purple')
elif (int(num1) > 6):
    print ('!Please choose numbers between 1-5!')
else:
    print ("You have entered your own color: " + str(num1))

Answer 1

将“红色”变成整数完全没有意义。所以用户不应该能够输入他们自己的颜色或输入颜色。他们必须输入一个整数，但这样就没有必要输入字符串了。

num1 = int(input('What is your favorite color? Choose a number from above: '))

Answer 2

这是因为不能将不是 int 的字符串转换为 int

If 子句首先计算括号中的条件，然后在计算结果为 True 时执行嵌套代码。

所以在你的代码中运行的第一件事是：

if (int(num1) == 1): ...

因此，要评估该语句的奇偶校验，它必须执行：

int(num1) == 1

但是如果 int(num1) 是一个字符串（如“green”），则 num1 不是未定义的。因此代码会产生错误。您需要做的是首先检查值 num1 是否为字符串，然后将其转换为数字后使用您的案例。

在python中有很多方法可以检查这是否是整数，可以考虑看看这里：https://www.pythonpool.com/python-check-if-string-is-integer/

最终代码可能类似于：

    One =  "1 = Red"
    Two = "2 = Blue"
    Three = "3 = Yellow"
    Four = "4 = Pink"
    Five = "5 = Purple"
    
    #Prints listed colors
    print ("*List of Colors below*")
    print (One + "\n" + Two + "\n" + Three + "\n" + Four + "\n" + Five)
    
    
    num1 = input('What is your favorite color? You can either choose the number from the list above or enter your own color: ')

    if !num1.isnumeric():
        print ("You have entered your own color: " + str(num1))
    elif (int(num1) == 1):
        print ('You chose the the first color from the list, which is: Red')
    elif (int(num1) == 2):
        print ('You chose the the first color from the list, which is: Blue')
    elif (int(num1) == 3):
        print ('You chose the the first color from the list, which is: Yellow')
    elif (int(num1) == 4):
        print ('You chose the the first color from the list, which is: Pink')
    elif (int(num1) == 5):
        print ('You chose the the first color from the list, which is: Purple')
    else (int(num1) > 6):
        print ('!Please choose numbers between 1-5!')

Answer 3

错误是由于尝试将非数字字符串转换为整数。您应该使用 try/except 构造：

num1 = str(input('What is your favorite color? You can either choose the number from the list above or enter your own color: '))
try:
    if (int(num1) == 1):
        print ('You chose the the first color from the list, which is: Red')
    elif (int(num1) == 2):
        print ('You chose the the first color from the list, which is: Blue')
    elif (int(num1) == 3):
        print ('You chose the the first color from the list, which is: Yellow')
    elif (int(num1) == 4):
        print ('You chose the the first color from the list, which is: Pink')
    elif (int(num1) == 5):
        print ('You chose the the first color from the list, which is: Purple')
    elif (int(num1) > 6):
        print ('!Please choose numbers between 1-5!')
except ValueError:
    print ("You have entered your own color: " + str(num1))

我不断收到 ValueError: invalid literal for int() with base 10: 'red'

3 个答案: