Cakephp DISTINCT

时间:2011-07-14 01:22:43

标签: php cakephp

如何使用DISTINCT获取total_time_driven_at_this_trip最高价值的唯一用户ID,并从另一个基于user_name的关系表中提取user_id?< / p>

我试过了......

$this->set('tripNsws', $this->TripNsw->find('all',array('limit' => 20,'fields' => array('DISTINCT(TripNsw.user_id)','TripNsw.total_time_driven_at_this_trip'),'group' => array('TripNsw.user_id') ,'order' => array('TripNsw.total_time_driven_at_this_trip desc'))));

但它不起作用。

我想你需要得到以下......

SELECT DISTINCT(user_id),`total_time_driven_at_this_trip` FROM `trip_nsws` order by `total_time_driven_at_this_trip` desc 

6 个答案:

答案 0 :(得分:8)

// see below url

    http://book.cakephp.org/1.3/view/1018/find


 array(
    'conditions' => array('Model.field' => $thisValue), //array of conditions
    'recursive' => 1, //int
    'fields' => array('Model.field1', 'DISTINCT Model.field2'), //array of field names
    'order' => array('Model.created', 'Model.field3 DESC'), //string or array defining order
    'group' => array('Model.field'), //fields to GROUP BY
    'limit' => n, //int
    'page' => n, //int
    'offset'=>n, //int
    'callbacks' => true //other possible values are false, 'before', 'after'
)



// or try this



function some_function() {

    $total = $this->Article->find('count');

    $pending = $this->Article->find('count', array('conditions' => array('Article.status' => 'pending')));

    $authors = $this->Article->User->find('count');

    $publishedAuthors = $this->Article->find('count', array(
    'fields' => 'DISTINCT Article.user_id',
    'conditions' => array('Article.status !=' => 'pending')
    ));

}

答案 1 :(得分:7)

在cakephp中纠正DISTINCT关键字的语法

$this->set('banners', $this->Banner->find('all',array('fields'=>'DISTINCT Banner.id')));

确保DISTINCT在字段数组中使用。

答案 2 :(得分:1)

正确的语法是

$this->set('tripNsws', $this->TripNsw->find('all',array('fields'=>'DISTINCT TripNsw.user_id')));

答案 3 :(得分:1)

您可以考虑将其设置为虚拟字段(http://book.cakephp.org/1.3/view/1608/Virtual-fields

$this->Model->virtualFields['distinct_user'] = 'DISTINCT Model.user_id';

答案 4 :(得分:0)

我总是在查询中使用GROUP BY来获得与DISTINCT

相同的结果

答案 5 :(得分:0)

'fields' => array('DISTINCT Model.Modelfield')

'fields' => array('Model.id','DISTINCT Model.Modelfield')