如何在XML数据中完成对以下代码/分组的分组

时间:2011-07-13 00:24:38

标签: sql-server sql-server-2005 sql-server-2008 xquery-sql

select               first name
              ,last name
               ,employeeID
                ,CASE
                     WHEN CONVERT(xml,detail).value('count(//education/item)','nvarchar(50)')=0 AND
                      CONVERT(xml,detail).value('(//preventive/itemValue/text())[1]','nvarchar(50)') LIKE '%Employee refuses to participate %' THEN
                           'AAA-1'

                       WHEN CONVERT(xml,detail).value('count(//education/item)','nvarchar(50)') =0 AND
                        CONVERT(xml,detail).value('count(//preventive/itemValue)','nvarchar(50)')=0 THEN
                            'AAA-2'
                        ELSE
                             'AAA-3'
                        END val

                        ,Start Date
                        ,End Date

FROM (HAS MULTIPLE JOINS HERE & CONDITION )



GROUP BY       first name
              ,last name
               ,employeeID
                ,CASE
                     WHEN CONVERT(xml,detail).value('count(//education/item)','nvarchar(50)')=0 AND
                      CONVERT(xml,detail).value('(//preventive/itemValue/text())[1]','nvarchar(50)') LIKE '%Employee refuses to participate %' THEN
                           'AAA-1'

                       WHEN CONVERT(xml,detail).value('count(//education/item)','nvarchar(50)') =0 AND
                        CONVERT(xml,detail).value('count(//preventive/itemValue)','nvarchar(50)')=0 THEN
                            'AAA-2'
                        ELSE
                             'AAA-3'
                        END 

                        ,Start Date
                        ,End Date

我的代码执行得非常好,但是当我编写group by子句时,它会抛出一个错误,指出XML数据类型无法分组。我知道我们可以通过用户定义的函数来完成它。谁能告诉我这项任务是如何实现的。我需要在我的代码中使用group by子句。我正在使用SQL Server 2005/2008。

1 个答案:

答案 0 :(得分:1)

您可以使用交叉应用在子查询中查询XML,然后使用字段列表和group by子句中子查询返回的值。

declare @T table(XMLCol xml)

insert into @T values
('<root>1</root>'),
('<root>2</root>'),
('<root>3</root>'),
('<root>3</root>')

select X.Value
from @T
  cross apply (select T.N.value('.', 'int')
               from XMLCol.nodes('root') as T(N)) as X(Value)
group by X.Value

结果:

Value
-----
1
2
3