处理程序没有在服务中呼叫？

Question

我从CallBack方法调用Handler，方法是，

public void callback(String fileName) {
        Log.d("Callback", "In call back method");
        System.out.println("--File = " + fileName);
        File d = new File(fileName);

        if (d.isDirectory()) {
            System.out.println("Is a directory ");
        } else {
            System.out.println("is a file");
            Bundle data = new Bundle();
            data.putString("path", fileName);
            Message msg = new Message();
            msg.setData(data);

           mfileObserver.sendMessage(msg);
            // mfileObserver.sendEmptyMessage(10);
            System.out.println("--msg is = " + msg);
            System.out.println("--File = " + fileName);
            //showDialog(fileName);

        }

我想通过处理程序调用活动，这里我将文件路径传递给activity.My处理程序代码是，

mfileObserver = new Handler() {
            public void handleMessage(Message msg) {
                 if (msg.what == 10) {
                final Bundle msgData = msg.getData();
                Log.d("FileObserverTest",
                        "handler " + msgData.getString("path"));
                System.out.println("in handler----- = ");
                System.out.println("path is----- = " + msgData.getString("path"));
                showDialog(msgData.getString("path"));

                // some(msgData.getString("path"));
                 }
            }
        };

请帮助我。

Answer 1

Intent dialogIntent = new Intent(this, CachingActivity.class);
Bundle bundle = new Bundle();
bundle.putInt("something", someInt);
dialogIntent .putExtras(bundle);
dialogIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
getApplication().startActivity(dialogIntent);