Question

如何在正则表达式中写入preg_match_all以“http”（不含引号）开头并以（“）或（'）或空格（制表符，空格，换行符）结尾

我想preg_match_all所有以“http”

开头的部分

Wupload
http://www.wupload.com/file/CCCCCCC/NNIW-LiBRARY.part1.rar
http://www.wupload.com/file/VVVVVVVV/NNIW-LiBRARY.part2.rar
http://www.wupload.com/file/TTTTTTT/NNIW-LiBRARY.part3.rar

Fileserve
http://www.fileserve.com/file/WWWW/NNIW-LiBRARY.part1.rar
http://www.fileserve.com/file/TTTTT/NNIW-LiBRARY.part2.rar
http://www.fileserve.com/file/RRRRR/NNIW-LiBRARY.part3.rar

Uploaded.To
http://ul.to/AAAA/NNIW-LiBRARY.part1.rar
http://ul.to/BBBBB/NNIW-LiBRARY.part2.rar
http://ul.to/YYYYYY/NNIW-LiBRARY.part3.rar

结果必须像这样 http://www.wupload.com/file/CCCCCCC/NNIW-LiBRARY.part1.rar
http://www.wupload.com/file/VVVVVVVV/NNIW-LiBRARY.part2.rar
http://www.wupload.com/file/TTTTTTT/NNIW-LiBRARY.part3.rar
http://www.fileserve.com/file/WWWW/NNIW-LiBRARY.part1.rar
http://www.fileserve.com/file/TTTTT/NNIW-LiBRARY.part2.rar
http://www.fileserve.com/file/RRRRR/NNIW-LiBRARY.part3.rar
http://ul.to/AAAA/NNIW-LiBRARY.part1.rar
http://ul.to/BBBBB/NNIW-LiBRARY.part2.rar
http://ul.to/YYYYYY/NNIW-LiBRARY.part3.rar

Answer 1

我建议您使用parse_url来获取部分网址！看一下php.net

编辑：

$file = file_get_contents( YOUR FILE NAME );
$lines = explode("\r\n", $file);
foreach( $lines as $line ){
$urlParts = parse_url( $line );
if( $urlParts['scheme'] == 'http' ){
 // Do anything ...
}
}

更改：

oOk，我不知道你的代码是什么！如果你想抓取html找到我建议的链接，它会返回一个标签的href值：

preg_match_all ( "/<[ ]{0,}a[ \n\r][^<>]{0,}(?<= |\n|\r)(?:href)[ \n\r]{0,}=[ \n\r]{0,}[\"|']{0,1}([^\"'>< ]{0,})[^<>]{0,}>((?:(?!<[ \n\r]*\/a[ \n\r]*>).)*)<[ \n\r]*\/a[ \n\r]*>/ is", $source, $regs );

for ( $x = 0; $x < count ( $regs [ 1 ] ); $x ++ ) {
$tmp_array [ "link_raw" ] = trim ( $regs [ 1 ] [ $x ] );
}

然后使用parse_url检查thoes

Answer 2

您是说要删除“Wupload”，“Fileserve”和“Uploaded.To”标题并仅捕获数组中的URL？如果是这样，请尝试以下操作：

preg_match_all('!^http://.*\n!m', $string, $matches);
echo "<pre>" . print_r($matches, 1) . "</pre>";

Answer 3

这应该做你需要的：

<?php
$matches = array();
preg_match_all('@https?://([-\w\.]+)+(:\d+)?(/([-\w/_\.]*(\?\S+)?)?)?@', $string, $matches);
foreach ($matches[0] as $match) {
    // Do your processing here.
}
?>

如何我preg_match_all以“http”开头，以（“）或（'）或空格（制表符，空格，换行符）结尾

3 个答案: