Question

我需要从字符数组中删除一个字符并重新调整数组的大小。到目前为止，我一直致力于用特殊角色替换特定角色。

在这段代码中，我正在搜索所有找到的匹配项，即如果在男性和女性角色数组中匹配任何字符，如果找到，我将用“*”替换它。而不是我必须删除该字符并调整数组大小。

private static void Compare(String Male,String Female) {

    char[] male;
    char[] female;
    // converting a string into charecter array

    male=Male.toCharArray();
    female=Female.toCharArray();

    //finding any matches i.e, any charecter is matching or not 
    for(int i=0;i<male.length;i++){

        for(int j=0;j<female.length;j++)
        {
            String m = Character.toString(male[i]);
            String fm = Character.toString(female[j]);
            if(m.equals(fm)){
            //if the charecters are equal  then  replacing them with "*"    

                male[i]='*';
                female[j]='*';

            }
        }
    }

Answer 1

试试这个：

    String male = "maleg*$m-z";
    String female= "femal^\\$e-is";
    String deletedMale = male.replaceAll("["+Pattern.quote(female)+"]", "");
    String deletedFemale = female.replaceAll("["+Pattern.quote(male)+"]", "");
    System.out.println(deletedMale);
    System.out.println(deletedFemale);

Answer 2

您可以在org.apache.commons.lang中使用ArrayUtils类库使这更容易： Array Utils Link

    public static void main(String[] args) {
        String Male = "male";
        String Female = "female";
        char[] male;
        char[] female;
        // converting a string into charecter array

        male=Male.toCharArray();
        female=Female.toCharArray();

        //finding any matches i.e, any charecter is matching or not 
        for(int i=0;i<male.length;){
        boolean remove = false;
            for(int j=0;j<female.length;)
            {
                String m = Character.toString(male[i]);
                String fm = Character.toString(female[j]);
                if(m.equals(fm)){
                //if the charecters are equal  then  replacing them with "*"    
                   female =  ArrayUtils.remove(female, j);
                   remove = true;
                }else{
                    j++;
                }
            }
            if(remove)
            {
                male =  ArrayUtils.remove(male, i);
            }else{
                i++;
            }
        }
        System.out.println(male);
        System.out.println(female);

}

Answer 3

嗯，您的代码存在很多问题。也就是说，缺乏惯例，没有回报价值，而且几乎没有明确问题究竟是什么。

无论如何，只有当字符出现在两个字符串中时，才会删除重复项。

private static void compare(String male, String female) {
    List<Character> male1 = addAll(male.toCharArray());
    List<Character> female1 = addAll(female.toCharArray());

    for (int i = 0; i < male1.size(); i++) {
        Character c = male1.get(i);
        if (female1.contains(c)) {
            while (male1.remove(c)) {
                i--;
            }
            while (female1.remove(c));
        }
    }

    // Do whatever else here, unless you need a char array, then convert it
    // if you need to.
    char[] maleA = toArray(male1);
    char[] femaleA = toArray(female1);

    System.out.println(new String(maleA));
    System.out.println(new String(femaleA));
}

以下是上述代码中引用的方法。

private static char[] toArray(List<Character> list) {
    char[] array = new char[list.size()];
    for (int i = 0; i < array.length; i++) {
        array[i] = list.get(i);
    }
    return array;
}

private static List<Character> addAll(char[] array) {
    List<Character> list = new ArrayList<Character>();
    for (char c : array) {
        list.add(c);
    }
    return list;
}

如果您需要使用其他数据类型，只需制作通用版本或更改它。

Answer 4

您可以使用以下功能轻松实现此目的：

String original_str="HOLLOW POOL";

String newone=original_str.replace("O", "*");     //Replaces the char "O" with "*"

System.out.print(newone);

结果将是H * LL * W P ** L

就是这样!!

如何从字符数组中删除特定位置的特定字符？

4 个答案: