Question

Excel 表格中的数据看起来像这样 Data 我首先按列读取数据，然后按行读取。Reading Data

一列相当于 15 分钟的时间段。在我的代码中，我将其捕获为 TimeID。

现在我想根据excel格式转换时间ID。例如：

Time ID = 5 显示 6 am
TimeID = 1 显示 5 am
TimeID = 2 显示 5:15 am 等等....


import pandas as pd
import io
from google.colab import files
uploaded = files.upload()
df2 = pd.read_excel(io.BytesIO(uploaded['202009 Testing - September - Diamond Plod Day & Night MKY021.xlsm']),sheet_name='1 D',header=16,usecols="G:BF",nrows=21)
df3 = pd.read_excel(io.BytesIO(uploaded['202009 Testing - September - Diamond Plod Day & Night MKY021.xlsm']),sheet_name='1 D',header=7,usecols="C",nrows=4,skiprows=range(0,1))
df=pd.DataFrame()
Activities=[]
TimeID=[]
HoleID=[]
for column in range(0,52):
   for row in range(0,21):
      if df2.iloc[row,column] == 'X':
       if row == 0:
        Activities.append('Safety Meetings (Client)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
     elif row == 1:
        Activities.append('Safety Meetings (McKay)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 2:
        Activities.append('Travel Time')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 3:
        Activities.append('Daily Pre-start Checks')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 4:
        Activities.append('Rig Move/Setup')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 5:
        Activities.append('Collaring the Hole ')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 6:
        Activities.append('Drilling')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 7:
        Activities.append('Surveys')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 8:
        Activities.append('Pulling Rods')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 9:
        Activities.append('Conditioning of Hole ')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 10:
        Activities.append('Reaming')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 11:
        Activities.append('Running Rods')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 12:
        Activities.append('Mixing Additives')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 13:
        Activities.append('Freeing stuck rods')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 14:
        Activities.append('Bit changes ')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 15:
        Activities.append('Casing operations – pull & run')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 16:
        Activities.append('Standby (explain in Driller comments)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 17:
        Activities.append('Breakdown (Maint. comments)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 18:
        Activities.append('Planned Maint. (Maint. comments)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 19:
        Activities.append('Other (explain in Driller comments)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])
    elif row == 20:
        Activities.append('Equip Inspections (explain in Driller comments)')
        TimeID.append(column+1)
        HoleID.append(df3.iloc[0,0])

 df['Activity'] = Activities
 df['TimeID'] = TimeID 
 df['HoleID'] = HoleID

需要将TimeID转成特定的excel格式。

Required Format

有人可以帮我吗？？

Google Colab：Code

Excel 文件：Attached

在python中以特定格式显示时间

0 个答案: