如果不在列表中，pandas 替换字符串值

Question

我有一个熊猫数据框

     city
0 los angeles
1 houston
2 new york
:
:
100 boston
:
:

如何将所有不在以下列表中的城市名称替换为other？

los angeles
saint petersburg
honolulu
Denverver
las vegas
saint louis
phoenix
houston
atlanta
philadelphia
orlando
chicago
san francisco
kailua kona

Answer 1

你可以这样做：

cities = ['los angeles',
 'saint petersburg',
 'honolulu',
 'Denverver',
 'las vegas',
 'saint louis',
 'phoenix',
 'houston',
 'atlanta',
 'philadelphia',
 'orlando',
 'chicago',
 'san francisco',
 'kailua kona']

df.loc[~df["city"].isin(cities), "city"] = "other"