我编写了一个简单的音乐机器人,其中包含 join
、play
、pause
、resume
和 leave
等命令。我遇到了一个问题,我将用一首歌曲运行 play
命令,它可以是 youtube 链接,也可以只是 youtube 视频的名称,它会播放大部分歌曲,然后它会随机停止播放。我假设这是 play
命令的问题,但我不确定。另一条信息是我将我的机器人托管在名为 Heroku 的网络托管服务上,但我认为这不是很重要,因为我在 Heroku 上设置了所有构建包,而且我在那里没有遇到任何问题.这是我正在使用的代码:
import asyncio
import discord
import youtube_dl
from discord.ext import commands
# Suppress noise about console usage from errors
youtube_dl.utils.bug_reports_message = lambda: ''
ytdl_format_options = {
'format': 'bestaudio/best',
'outtmpl': '%(extractor)s-%(id)s-%(title)s.%(ext)s',
'restrictfilenames': True,
'noplaylist': True,
'nocheckcertificate': True,
'ignoreerrors': False,
'logtostderr': False,
'quiet': True,
'no_warnings': True,
'default_search': 'auto',
'source_address': '0.0.0.0' # bind to ipv4 since ipv6 addresses cause issues sometimes
}
ffmpeg_options = {
'options': '-vn'
}
ytdl = youtube_dl.YoutubeDL(ytdl_format_options)
class YTDLSource(discord.PCMVolumeTransformer):
def __init__(self, source, *, data, volume=0.5):
super().__init__(source, volume)
self.data = data
self.title = data.get('title')
self.url = data.get('url')
@classmethod
async def from_url(cls, url, *, loop=None, stream=False):
loop = loop or asyncio.get_event_loop()
data = await loop.run_in_executor(None, lambda: ytdl.extract_info(url, download=not stream))
if 'entries' in data:
# take first item from a playlist
data = data['entries'][0]
filename = data['url'] if stream else ytdl.prepare_filename(data)
return cls(discord.FFmpegPCMAudio(filename, **ffmpeg_options), data=data)
class Music(commands.Cog):
def __init__(self, bot):
self.bot = bot
@commands.command(description="joins a voice channel")
async def join(self, ctx):
if ctx.author.voice is None or ctx.author.voice.channel is None:
return await ctx.send('You need to be in a voice channel to use this command!')
voice_channel = ctx.author.voice.channel
if ctx.voice_client is None:
vc = await voice_channel.connect()
else:
await ctx.voice_client.move_to(voice_channel)
vc = ctx.voice_client
@commands.command(description="streams music")
async def play(self, ctx, *, url):
async with ctx.typing():
player = await YTDLSource.from_url(url, loop=self.bot.loop, stream=True)
ctx.voice_client.play(player, after=lambda e: print('Player error: %s' % e) if e else None)
embed = discord.Embed(title="Now playing", description=f"[{player.title}]({player.url}) [{ctx.author.mention}]")
await ctx.send(embed=embed)
@commands.command(description="pauses music")
async def pause(self, ctx):
ctx.voice_client.pause()
await ctx.send("Paused ⏸️")
@commands.command(description="resumes music")
async def resume(self, ctx):
ctx.voice_client.resume()
await ctx.send("Resuming ⏯️")
@commands.command(description="stops and disconnects the bot from voice")
async def leave(self, ctx):
await ctx.voice_client.disconnect()
@play.before_invoke
async def ensure_voice(self, ctx):
if ctx.voice_client is None:
if ctx.author.voice:
await ctx.author.voice.channel.connect()
else:
await ctx.send("You are not connected to a voice channel.")
raise commands.CommandError("Author not connected to a voice channel.")
elif ctx.voice_client.is_playing():
ctx.voice_client.stop()
def setup(bot):
bot.add_cog(Music(bot))
其他人也遇到了同样的问题,并在 stackoverflow 上发布了相关信息,但似乎没有人对这些问题做出回应。我检查了 Github 存储库和许多其他网站,包括 stackoverflow,但我没有运气。如果有人能帮助我,我将不胜感激!
答案 0 :(得分:1)
问题在于 FFMPEG 可执行文件从网络主机获取损坏的数据包,导致其终止。
您可以通过在 discords loglevel
类中手动将 verbose
设置为 FFmpegPCMAudio
来查看这一点。
由于我们宁愿重新连接也不愿提前终止歌曲,因此您可以将 ffmpeg_options
更改为以下内容:
ffmpeg_options = {
'options': '-vn',
"before_options": "-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5"
}
这是一个使用这些参数的完整机器人:Lenart12's MusicBot